Recent content by Imo

Hi, I'ld like the solutions to Zwiebach as well. My e-mail address is quicksilver06 [at] hotmail.com . Thanks

You just have to realize you have a regular kinematics question in 1D now. You know the initial speed and you know the acceleration. That should be enough to find the distance and time.

do you remember what the meaning of the co-efficients of the plane are? I suggest you look that up, and then remember that all you need to make the equation of a line is a directional vector and a point. That's the absolute simplest way to do it. The parametric equations come straight from that.

try your local reference library for physics magazines, you'll be suprised how many there are. My favourite is Scientific American.

Some useful hints: a^\frac{b}{c} = (a^b)^\frac{1}{c} = (a^\frac{1}{c})^b a^-^b = \frac{1}{a}^b a^\frac{1}{b} = \sqrt[b]{a} hope that helps

if you can't conceptualize the problem, why don't you try to actually do it experimentally? It's not very hard to make this experiment in your kitchen and it might just give you the visualization you need for the next questions.

Actually, your already done...you just don't know it. remember that tanx=sinx/cosx? try that this one is done. again, remember that cotx=1/tanx, so what is cotx in terms of sin and cos?

Incidentally I did the exam same project in grade 12 and I still remember enough of how it works. I'll start with the whole reason why the motor works. You have two permanent magnets spaced apart with opposite polarizations (north or south) and a set of electromagnets rotating between them. The...

ok, calm down. This isn't really that hard, it's just in a new format. I assume that you've done gravity? F=\frac{G m_{1} m_{2}} {r^2}? Well coulomb's law is basically the same. Instead of G you have k, and instead of masses you have charges. So for the force between two charges, you just put q1...

Unless I'm missing something (which is entirely possible), is that not what I have?

"Find the volume of the region enclosed between the survaces z=x^2 + y^2 and z=2x" I figured that the simplest way of doing this was to switch to a cylindrical co-ordinate system. Can someone check that the limits of integration are then -\frac{\pi}{2}\leq \theta \leq\frac{\pi}{2} 0\leq\ r...

Actually, those aer the same answers (up to that constant, if you put it directly into your calculator, they differ already by a constant that doesn't matter in this type of integration...add 1/48 to your answer to get the other). They just went another direction in the integration.

I suggest going to www.mathworld.com and typing in some of the keywords used in the replies. Specifically look up "Riemann Sum", "Integration" (at least on of these links will give you a brief history), and click on some of the links at the bottom of the page that catch your fancies.

xanthym, that was quite an amazing proof. Very hard to see it because it is so simple. Except for going from step 7 to 8. That is a very easy step to miss.

Well let's work through this... What causes the tension? Cart A pulling on Cart B (think about you pulling on a string attatched to a cart. Your pulling causes the tension) So what is the force of Cart A pulling on Cart B? There are 4 forces that you are given to work with. 1) Friction...