Hi everyone...I am in my last semester of college and physics has returned to my life.. It has been approximately 3 yrs since physics and 6 years since calculus so I am really rusty regarding classical physics (mechanics).
here is my problem
Listed below are three vectors that point from...
yes i did draw it but i think my problem is that I'm not good at drawing vectors...thats my problem the way i did it the angle looked like it was 60 degrees
ok i did the law of cosines knowing that the answer is supposed to 15.7 N and i got the angle to be 120 degrees...is that possible?
are you sure the angle between 7.2 and 10.8 isn't supposed to be 60, because the way i have it made up the 120 degree angle is the angle that is made between the...
oh man...im sorry I'm now confused i thought I had it right...
so let me get this straight i have the two force vectors right of 7.2 and 10.8
and they are the side of a new triangle...and the other line that connects those two force vectors together will be the resultant that I'm looking...
ok i think i might have conveyed what I've done in the problem badly so i'll explain a bit more thoroughly what i did because there seems to be some confusion on my part and doing this usually helps me think through
well i setup the triangle so that A and P were on the horizontal and P was on...
Three point charges of +2μC, +3μC and +4μC are at the vertices of an equilateral triangle ABP, respectively, having sides of 10cm. What is the resulting force R acting on the +4μC charge?
the hint in class is to use the law of cosines
this is how i set it up
force acting on 4uc from...
arrrrggh! lol i hate my textbook I'm seriously it doesn't say that! no joke and same with my notes i had to research that online
but thank you for your help that just solidifed with what i just learned. i apprecaite it =)
2 Capacitors, C1 = 3*10^-12 f and C2= 6*10^-12 f are connected in series and the resulting combination is connected across 1000V
a) the equivalent capacitance
i got this 1/Ctotal = 1/C1 + 1/C2
b) total charge on the combination and the charge taken by each capicator
ok here is where i...
ok then...what formula do i use to calculate E fields given this information...thats how i was thinking to get to E using that equation
electric field = voltage/radius = E = V/r by the way
i got it from my professor in lecture
hi I don't exactly know how to approach this problem
Compute the electric field in air midway bewteen two point charges of 20*10^-8C and -5*10^-8C separated by a distance of 10cm
i was thinking of finding V of both the charges and finding the difference between them
so V1 =...
a quantity of gas in a cylinder receives 1600J of heat from a hot plate. At the same time 800J of work are done on the gas by outside forces pressing down on a piston. Calculate the change in thermal energy of the gas
Input heat Q = 1600J
The amount of work done on the gas is, W = 800J...
so curious would the summation of the forces in the y direction be
Sin40T + F1 (force rod is connected to the wall) = 400 N + 500 N
and but then the sum of the torque is getting me mixed up
if i choose the point where the rod is connected to the wall as the axis of rotation do I include...
ok so essentially then then impulse = momentum since the initial momentum = 0
so 8.83 N*s = (.44 kg) * V
then solve for V...??
if so wow that was kinda easy