Recent content by inky

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    Minimum speed at the circular track

    Thanks a lot. Why didn't consider the force at the top?
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    Minimum speed at the circular track

    Homework Statement What is the minimum speed of the car must have at the top of the loop? There are three methods. I would like to know which method or answer is correct. Please see attached file. Homework Equations Please see attached file. The Attempt at a Solution Please...
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    Conservation momentum for y- axis

    No. We could not use Law of conservation of momentum for falling objects because of the external force acting on it. I don't want the answer. I want correct method.
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    Conservation momentum for y- axis

    Please see examiner report.Pls. see attachment.
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    Conservation momentum for y- axis

    If the time duration of the collision was nonzero, the collision force would have to be specified as a function of time. If it was a nice constant force you could work out the motion during the collision beginning with an F = ma formula for each mass. Looks complicated. The answer would not...
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    Conservation momentum for y- axis

    Homework Statement A ball P of mass m kg is dropped from a point A, which is 2 m vertically above a point B on a horizontal floor. After P hits the floor at B, it rebounds and hits another ball Q, of the same mass, which has also been dropped from A. The impact between the two balls is...
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    Two bodies attracting via gravitation

    When I calculate the problems for collision, e=(speed of separation)/(speed of approach) If two bodies are moving opposite directions, relative velocity is v1+v2. If two bodies are moving same direction, relative velocity is v2-v1. After collision two bodies need to separate. It...
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    F = m x a, but what if velocity is constant (making a zero)?

    I think before collision speed of truck is constant but after collision speed is not constant. So it has acceleration. Now we can consider force.
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    (M1 x 1)+(M2 x2) / M1+M2

    You took the wrong value. We don't know xb and yb We know centre of mass where is it. x(bar) (or) xc=2, y(bar) or yc=5.5 Use xc=(m1x1+m2x2)/(m1+m2) . You can find x2. yc formular is similar as xc. You can find y2.
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    Simple coefficient of friction problem

    Read the problem again. Constant speed!!! Equilibrium condition!!
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    Help with inclined plane

    Draw the diagram for initial and final position for the object. Use law of conservation of energy at the top and distace d from the bottom.
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    Revolutions and angular speeds

    You forgot to do square for v0. So calculate again.
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    Torque problem

    Wow!!Take the axis at point P is very easy to calculate. Thanks .