How Many Revolutions Do Tires Make Before Stopping?

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SUMMARY

The discussion focuses on calculating the number of revolutions each tire makes before a car comes to a stop, given an initial speed of 33.8 m/s and a constant negative acceleration of 1.80 m/s². The correct approach involves using the kinematic equation v² = v₀² + aΔx, leading to a total stopping distance of 9.39 meters. This distance translates to 1.49 revolutions for tires with a radius of 0.330 meters. Additionally, the angular speed of the wheels at half the total distance must be calculated, emphasizing the importance of accurate initial conditions in physics problems.

PREREQUISITES
  • Understanding of kinematic equations, specifically v² = v₀² + aΔx
  • Knowledge of angular motion concepts, including revolutions and radians
  • Familiarity with basic physics principles of acceleration and deceleration
  • Ability to perform unit conversions between linear and angular measurements
NEXT STEPS
  • Calculate the total stopping distance using different initial speeds and accelerations
  • Explore the relationship between linear speed and angular speed in rotating systems
  • Investigate the effects of tire radius on the number of revolutions during deceleration
  • Learn about friction and its role in vehicle stopping distances
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as automotive engineers and anyone interested in vehicle dynamics and stopping distances.

mandy9008
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Homework Statement


A car initially traveling at 33.8 m/s undergoes a constant negative acceleration of magnitude 1.80 m/s2 after its brakes are applied. (a) How many revolutions does each tire make before the car comes to a stop, assuming the car does not skid and the tires have radii of 0.330 m? (b) What is the angular speed of the wheels when the car has traveled half the total distance?


The Attempt at a Solution


v2=vo2 + aΔx
0= 33.8 m/s + 2(-1.8 m/s2)Δx
Δx=9.39
Δө=9.39 rad / 2π = 1.49 rev
 
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mandy9008 said:

Homework Statement


A car initially traveling at 33.8 m/s undergoes a constant negative acceleration of magnitude 1.80 m/s2 after its brakes are applied. (a) How many revolutions does each tire make before the car comes to a stop, assuming the car does not skid and the tires have radii of 0.330 m? (b) What is the angular speed of the wheels when the car has traveled half the total distance?


The Attempt at a Solution


v2=vo2 + aΔx
0= 33.8 m/s + 2(-1.8 m/s2)Δx
Δx=9.39
Δө=9.39 rad / 2π = 1.49 rev

You forgot to do square for v0. So calculate again.
 

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