Recent content by irony of truth

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    Fixed-Point Iteration for Nonlinear System of Equations

    Hi Karlisbad: F(x,y,z)=0 I believe that this will be effective for the Newton's Method, which I got one of its solutions using a scilab program. It's pretty difficult for me to use the fixed point iteration, but I am hoping that somehow, I can get that fixed point.
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    Ramanujan Summation & Riemann Zeta Function: Negative Values

    Actually... I have thought of a proof for that.. but without that "R". I hope this helps... You first consider the "-" summation (from i = 1 to infinity) of i(-r)^i. Let this sum be equal to S. Then, S = r - 2r^2 + 3r^3 - 4r^4 + ... - ... Sr = 0 + r^2 - 2r^3 + 3r^4 - ... + ...
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    Fixed-Point Iteration for Nonlinear System of Equations

    Hello: I am solving for the fixed point of this nonlinear system: x^2 - x + 2y^2 + yz - 10 = 0 5x - 6y + z = 0 -x^2 - y^2 + z = 0 Somehow, I got stuck with my function for g, g(x) = x. I ran this in a program applying the Newton's method and I got its...
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    (Complex Variables) Differentiability of Arg z

    I am proving that the function f(z) = Arg z is nowhere differentiable by using the definiton of a derivative. I let z = x + yi. Then, if the limit exists, we have f'(z) = lim (/\z -> 0) ( f(z + /\z) - f(z) ) / /\z. (Note that /\ is the triangle symbol) Also, let /\z = p + iq, where p and...
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    Proving on modulus and conjugates

    I am proving that (sqrt)2 |z| >= |Re z| + |Im z|. The professor gave this as an example, but I want to ask something... Why is it that I can't use this strategy: -> |Re z| <= |z| -> |Im z| <= |z| -> adding corresponding expression yields |Re z| + |Im z| <= 2|z|. (what's wrong here?)
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    Trig Identity: Solving \cos \theta (\tan \theta + \cot \theta) = \csc \theta

    So, are you proving this identity? Express your tangent and cotangent in terms of sine and cosine. Get their LCD... and your numerator becomes a well-known trigonometric identity.. Can you continue from here? :D
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    All about sequence of functions

    Thank you for clarifying... yes, it should have been n^2 + n.
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    All about sequence of functions

    Let {h_n} be a sequence of function defined on the interval (0,1) where h_n(x) = (n+n)x^(n-1)(1-x) a. find lim (n-> +oo) (integral) (from 0 to 1) h_n(x) dx. b. show that lim (n-> +oo) h_n(x) = 0 on (0, 1) c. Show that lim (n-> +oo) (integral) (from 0 to 1) h_n(x) dx is not equal to...
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    On uniform convergence of sequence

    Suppose (f_n} is a sequence of functions where f_n(x) = x / (1 + n^2 x^2). I am finding the pointwise limit of the sequence of {f_n'(x)} on the interval (-oo, + oo)...in which {f_n'(x)} is the sequence of functions obtained from the derivative of x / (1 + n^2 x^2) and I am trying to find...
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    Is There a Time Difference Calculator That Works with Delphi?

    Is there a site which has a "program" that allows me to enter two dates and then the program will compute the length of time between these two dates?
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    Which is correct? Proving - numerical analysis (separation of symbols)

    Proving - numerical analysis (separation of symbols) How do I prove this? f(x+n) = f(x+n-1) + /\f(x+n-2) + ... + /\^(n-2) f(x+1) + /\^(n-1) f(x) + /\^n f(x-1)
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    Proving Uniform Continuity on a Closed Bounded Interval

    Thank you for the help...
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    Proving Uniform Continuity on a Closed Bounded Interval

    How do I prove that when a function f is continuous on a closed bounded interval [a,b], it is uniformly continuous on that interval? Actually, I have found some proofs to this but I have not tackled about compact, Heine-Borel theorem, metric spaces, sequences and series, etc. in my class..
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    Some clarifications on my proving

    From what I understand, he/she is saying that S is dense in the set of real numbers... continuing further, if a and are real nos. and a < b, there is an s belonging to S such that a < s < b.
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    Infinite Set S w/ Least Upper Bound & Acc. Point - Example?

    Ah.. ok.. I asked that because I thought the proof only shows that /\ is the least upper bound... and not that /\ is an accumulation point. From the proof HallsofIvy stated, how did /\ turn out in the end to be an accumulation point (I apologize for being "slow")
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