Recent content by izelkay

Will be interfacing with the NI 6356 next week, but ultimately plan to use an NI PCI-6123.

Oh looks like the datasheet is more specific. 100Gohms in parallel with 10pF. Though I'm still not sure what to do with this information. I'm thinking the DAQ input impedance should be really high while the preamp output impedance should be really low since the DAQ is sensing voltage. Similarly...

Yes I know it won't be simple but I need to start somewhere and I thought impedance requirements was a suitable starting point, but I'm not sure how the input and output impedances should relate. Everywhere I search says something different or isn't clear. For now I would just like to know how...

Oh yes, sorry forgot to mention but I'll have the hydrophone go to a preamplifier first, then the DAQ. So would the preamplifier need a high input impedance and a low output impedance? I plan to design/build one

It's a Reson TC4013 hydrophone, and it's datasheet: http://www.teledyne-reson.com/download/hydrophone_data_sheets__/TC4013.pdf gives me some information about its impedance at different frequencies. It's much lower than the ADC input of the DAQ (>100 Gohms). So would I need to make these...

Hello, I'm confused about the concept of impedance matching in regards with hydrophones and DAQs. If the input impedance to an ADC channel on a DAQ is very high, would I need whatever's being fed into it (hydrophone) to also need a high impedance? Or would it need a low impedance? I've tried...

It looks like I'd actually need to feed Instruction[10:6] and Instruction[15:0] into another Mux and have it select Instruction[10:6] when I want to shift, which will then be sent through the sign extender and into the ALU when ALUSrc is set to 1. Right? Anyone?

Homework Statement Here's the datapath: So this seems like a pretty common question but I can't seem to find any answers on how to extend the datapath to implement SLL and SRL.The Attempt at a Solution This is how I would think to do it but I'm not entirely sure: It would need another mux...

Yeah we're assuming ideal components. The non-idealities come into play for the lab portion of this class.

Ohh okay I think I'm starting to get it now. Ideally, a FWR with cap filter would output a pure DC voltage. That's why (depending on the capacitor value) I can use the DC power formulas (P = IV, P = V²/R), even though there's a small voltage ripple. But with a FWR without a cap filter, I need to...

Right, I understand that. Okay I'm sorry but I'm still having trouble understanding. I know what rms means but it's confusing me in this instance. In a full-wave rectifier without cap filter, the output voltage would be the fully rectified input sinusoid, and the rms would be double the hwr...

Using the equation it'd be 6 Ω. But is it different for half-wave rectifiers then? I'm looking at this example in my book and it's using RMS to calculate the power (part b): But the output of a HWR is DC too isn't it?

Oh okay so then with my turns ratio, ΔVo = 12.12*0.03 = 0.3636 V Hm I'm a bit confused, how else would I calculate the power absorbed by the resistor here? Everything else we've done so far has it as either P = V2rms/R or P = I2rmsR. Or because it's DC, should it just be 12.122/R without...

Homework Statement I'm having trouble understanding part C of this question. Homework Equations ΔVo = Vout/2fRC The Attempt at a Solution So to get ~12V at the output, the turns ratio should be 14 because 120√2/12 = 14.14. Using a turns ratio of 14, the output voltage will be 12.12 V. To...

Yep my mistake, 0.025 mm. Thanks for your help; much appreciated.