Recent content by jacksonjs20
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Graduate Need help finding a bound for an equation
Thank you very much. I would have been stuck for hours.- jacksonjs20
- Post #3
- Forum: Calculus
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Graduate Need help finding a bound for an equation
I'm trying to find a value K>o such that for real a,b,c,d (a^2+c^2)x^2+2(ab+cd)xy+(b^2+d^2)y^2 ≤ K(x^2+y^2). Any help on this would be greatly appreciated thanks.- jacksonjs20
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- Bound
- Replies: 2
- Forum: Calculus
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Graduate Continuous Function? g(x): Real Q & Non-Q Cases
I have come to the conclusion that g must be differentiable at x=0, and thus continuous, since the limit of the difference quotient from above and below exist and are equal. Is this correct? If so what is the most efficient method of proving that it is not differentiable at any other points...- jacksonjs20
- Post #4
- Forum: Calculus
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Graduate Continuous Function? g(x): Real Q & Non-Q Cases
let g:R->R be a real function defined by rule g(x) = x^2 if x\in\mathbb{Q} and g(x) = 0 if x\notin\mathbb{Q} is g continuous (*on R)? Many thanks in advance *thanks for pointing out mistake above.- jacksonjs20
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- Continuous Function
- Replies: 6
- Forum: Calculus
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Undergrad Problem with differential equation
Hi could someone please explain why (1-x^2)y'' = 2xy'-2y Many thanks in advance.- jacksonjs20
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- Differential Differential equation
- Replies: 3
- Forum: Differential Equations
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Undergrad Is a Real funcion with a Limit Bounded?
Hi, just a quick question. Let f be real function s.t. the limit of f as x approaches a equals L. Is f bounded? i.e. is it sufficient to assume a function is bounded if it has a limit. Thanks to all who may reply.- jacksonjs20
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- Bounded Limit
- Replies: 5
- Forum: Calculus
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Graduate Confused by separate definitions of sets which are bounded above
Thank you for your prompt reply. That is exactly the response i was looking for. Just to clarify The existence of an m > 0 is a necessary condition for a set to be bounded above. Though, provided it exists, an m < 0 which is an upper bound is sufficient to justify that a set is bounded above...- jacksonjs20
- Post #3
- Forum: Calculus
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Graduate Confused by separate definitions of sets which are bounded above
I have been consulting different sources of analysis notes. My confusion comes from these two definitions \begin{defn} Let S be a non-empty subset of $\mathbb{R}$. \begin{enumerate} \item $S$ is Bounded above $ \Longleftrightarrow\exists\,M > 0$ s.t. $\forall\, x\in S$, $x\leq M$...- jacksonjs20
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- Bounded Confused Definitions Sets
- Replies: 3
- Forum: Calculus