Recent content by Jaco Leo

Here's the actual answer, this might help you. But that ln(b) term still doesn't make sense to me.

Ok yeah that makes sense, so the (λ*L/2piε0(L-y)) * ln(b/a)) term is describing the displacement of the inner cylinders potential. But I'm still very confused about the second term (λ*L/2piε0y) * ln(b). Is this describing the potential left within the system? Honestly can't figure that out, and...

So it looks like to find the voltage when the inner cylinder moves a distance y, it takes into account two different electric fields to be integrated? because you've got two terms in the answer. Also there's a y in the denominator in the first term and a (L-y) in the denominator in the 2nd term...

λ is the line charge, and I actually already know the answer to this question, it's (λ*L/2piε0y) * ln(b) + (λ*L/2piε0(L-y)) * ln(b/a)), where L is the length of the cylinder and y is the displacement of the inner cylinder along the axis. I'm just not sure how they got to this answer. I'm not...

Homework Statement . Trying to find the potential between a variable capacitor that is made up of two coaxial cylinders of radii a and b, with (b-a) << a, when inner cylinder displaced by a distance y along axis. 2. Homework Equations E = λ / 2piε0r V = λ/2piε0 * ln(b/a) when there is...

Homework Statement If you have a large telescope that has a 5 meter diameter with a field of view of 1 foot by 1 foot, and a small telescope with a diameter of 1 meter with a field of view of 1 degree by 1 degree, and your trying to take images of 30 quasars that has a limiting visual magnitude...

do you use kinematic equations to figure this out then?

Here's what I came up with so far. I know sin of the angle = Vy/V and cos of the angle = Vx/V. Then do some algebra to get Vy = Vsin of angle and Vx=Vcos of angle. But since It doesn't list a velocity in the problem, how are you actually suspose to get a value for the x and y components of the...

but there is no known velocity or angle in the problem?

the total distance seems to be 20m and there will always been a downward force of 9.8m/s^2 which is gravity. I just don't know how to start to find the velocity, and the only angle that i see is maybe a 90 degree angle? But I'm not sure about that either.

still don't really understand how to properly answer the questions. How do i actually figure out the x and y components based on the information? Do I set it up in a Axi + Ayj type of format?

Homework Statement You’re 5.00 m from the left-hand wall of the house shown in the drawing, and you want to throw a ball to a friend 5.00 m from the right-hand wall. You throw the ball so that at the peak of its trajectory it just clears the top of the roof...