Recent content by Jaco Leo
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Finding the potential between two coaxial cylinders
Here's the actual answer, this might help you. But that ln(b) term still doesn't make sense to me.- Jaco Leo
- Post #10
- Forum: Advanced Physics Homework Help
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Finding the potential between two coaxial cylinders
Ok yeah that makes sense, so the (λ*L/2piε0(L-y)) * ln(b/a)) term is describing the displacement of the inner cylinders potential. But I'm still very confused about the second term (λ*L/2piε0y) * ln(b). Is this describing the potential left within the system? Honestly can't figure that out, and...- Jaco Leo
- Post #8
- Forum: Advanced Physics Homework Help
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Finding the potential between two coaxial cylinders
So it looks like to find the voltage when the inner cylinder moves a distance y, it takes into account two different electric fields to be integrated? because you've got two terms in the answer. Also there's a y in the denominator in the first term and a (L-y) in the denominator in the 2nd term...- Jaco Leo
- Post #5
- Forum: Advanced Physics Homework Help
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Finding the potential between two coaxial cylinders
λ is the line charge, and I actually already know the answer to this question, it's (λ*L/2piε0y) * ln(b) + (λ*L/2piε0(L-y)) * ln(b/a)), where L is the length of the cylinder and y is the displacement of the inner cylinder along the axis. I'm just not sure how they got to this answer. I'm not...- Jaco Leo
- Post #3
- Forum: Advanced Physics Homework Help
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Finding the potential between two coaxial cylinders
Homework Statement . Trying to find the potential between a variable capacitor that is made up of two coaxial cylinders of radii a and b, with (b-a) << a, when inner cylinder displaced by a distance y along axis. 2. Homework Equations E = λ / 2piε0r V = λ/2piε0 * ln(b/a) when there is...- Jaco Leo
- Thread
- Coaxial Cylinders Physics Potential
- Replies: 9
- Forum: Advanced Physics Homework Help
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X and y components of initial velocity
do you use kinematic equations to figure this out then?- Jaco Leo
- Post #15
- Forum: Introductory Physics Homework Help
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X and y components of initial velocity
Here's what I came up with so far. I know sin of the angle = Vy/V and cos of the angle = Vx/V. Then do some algebra to get Vy = Vsin of angle and Vx=Vcos of angle. But since It doesn't list a velocity in the problem, how are you actually suspose to get a value for the x and y components of the...- Jaco Leo
- Post #13
- Forum: Introductory Physics Homework Help
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X and y components of initial velocity
but there is no known velocity or angle in the problem?- Jaco Leo
- Post #9
- Forum: Introductory Physics Homework Help
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X and y components of initial velocity
the total distance seems to be 20m and there will always been a downward force of 9.8m/s^2 which is gravity. I just don't know how to start to find the velocity, and the only angle that i see is maybe a 90 degree angle? But I'm not sure about that either.- Jaco Leo
- Post #7
- Forum: Introductory Physics Homework Help
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X and y components of initial velocity
still don't really understand how to properly answer the questions. How do i actually figure out the x and y components based on the information? Do I set it up in a Axi + Ayj type of format?- Jaco Leo
- Post #4
- Forum: Introductory Physics Homework Help
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X and y components of initial velocity
Homework Statement You’re 5.00 m from the left-hand wall of the house shown in the drawing, and you want to throw a ball to a friend 5.00 m from the right-hand wall. You throw the ball so that at the peak of its trajectory it just clears the top of the roof...- Jaco Leo
- Thread
- Components Initial Initial velocity Velocity
- Replies: 15
- Forum: Introductory Physics Homework Help