Recent content by jam_27

found it http://eu.wiley.com/WileyCDA/WileyTitle/productCd-0471981958.html

close, but this is not the one.

I remember using matrix notation in my course on optical waveguide theory many years ago. The lecturer was using a textbook which I cannot remember. I have since misplaced my course notes. I was wondering if anyone could direct me to the source textbook? The notation (Eq. 2.20) is attached...

Can anyone identity the book please? http://atao.ucsd.edu/258/bandbending.pdf i had some notes from this book. I need more info. with great difficulty I have been able to find the link. any leads will be very useful. thanks

Thanks, I have corrected the typo and also the original problem definition. Please see if its ok now.

I know about the Lambert W-function. As I said, above is a simplified version of my actual problem. so I specifically need to know if my last 2 steps are valid operations. Thanks

Say I have a function, f(x) = x sec (f(x)) [this is just an example function, the actual problem is more complicated] g(x) = x f(x), then using integration by parts, I can write I = a∫bg(x) dx = a∫bx f(x) dx = (f(x) \frac{x^{2}}{2})|^{b}_{a}- \frac{1}{2}a∫b\frac{d f(x)}{dx} x2 dx...

Do you mean that I integrate in (x,y) but over the curve \check{y}?

Exactly. So, assuming I have done everything correctly - here are the details. I am trying to evaluate 0∫1y(x,y)dx, where y= (a+b)*x - b*x*exp(p*x+q*y) - c*(p*x2 + q*y) with a, b, c, p and q all known constants. Also, its known that y = 0 at x = 0 and y = 0 at x =1. Now using...

Its not a HW problem. I am trying to solve an integral where the integrand is a transcendental function. Using the coordinate transformation here, I came up with the above coordinate transformation for my case. What I need to do now is to draw the new \hat{x}\hat{y} on top of x,y cartesian...

How can I geometrically interpret this coordinate transformation (from x,y space to \check{x},\check{y} space)? x = \check{x}cos(β) - \check{y}sin(β) y = \frac{1}{2}(\check{x}2 -\check{y}2)sin(2β) -\check{x}\check{y}cos (2β)

Ok, then, how much can we proceed to? I mean can we write G (x) in terms of S, a and b plus some unknown? Also, b=1 and a= 0 and S is a constant in my case.

Is this possible.. Say, a∫b f(x)dx = G(x)|x=b - G(x)|x=a = S, where S, a and b are known. Can we find G(x) ?

Nope, not possible with what I know.

I am wondering if I can use rotation of coordinates to solve this integral, like here, Example D.9? Looking for some direction...