Recent content by james brug
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Answer: The mass of the piston is 16.2 kg.Weight of a Piston: 16.2 kg
Homework Statement A vertical cylindrical tank contains 1.80 mol of an ideal gas under a pressure of 1.05 atm at 22.0^\circ C. The round part of the tank has a radius of 10.0 cm , and the gas is supporting a piston that can move up and down in the cylinder without friction. What is the...- james brug
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- Piston Weight
- Replies: 1
- Forum: Introductory Physics Homework Help
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Thermal Expansion Ethanol Problem
How did you find part A? ? You are supposed to account for the contraction of the cylinder.- james brug
- Post #5
- Forum: Introductory Physics Homework Help
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Transverse wave equation period
A transverse wave on a rope is given by y(x, t)= (0.750\; {\rm cm})\, \cos ( \, \pi [(0.400\;{\rm cm}^{ - 1})x+(250\; {\rm s}^{ - 1})t]) Find the period. This should be simple, but I keep getting the wrong answer in Mastering Physics. I can't find any explanation in my book, and it's...- james brug
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- Period Transverse Transverse wave Wave Wave equation
- Replies: 1
- Forum: Introductory Physics Homework Help
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Minimum Speed of a Rock: Solving Problem with Pit Gap of 40m
Yes, that is correct. \sqrt{1372\;m^2/s^2+(19.8\;m/s)^2} = Life, the Universe, and Everything- james brug
- Post #11
- Forum: Introductory Physics Homework Help
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Minimum Speed of a Rock: Solving Problem with Pit Gap of 40m
I have found the answer.- james brug
- Post #9
- Forum: Introductory Physics Homework Help
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Minimum Speed of a Rock: Solving Problem with Pit Gap of 40m
Can someone please help ?- james brug
- Post #8
- Forum: Introductory Physics Homework Help
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Minimum Speed of a Rock: Solving Problem with Pit Gap of 40m
The solution to this should be the initial velocity it takes to get to top of the hill plus the velocity needed to clear the pit, right? I get about 56.8 m/s which is apparently wrong. \sqrt{1372}\;m/s+19.8\;m/s- james brug
- Post #7
- Forum: Introductory Physics Homework Help
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Calculating Work in a Pulley System
I had already found that out, but thanks anyway.- james brug
- Post #12
- Forum: Introductory Physics Homework Help
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How Is Total Work Calculated for Two Connected Blocks with Friction?
Never mind. I've solved it myself through some careful research and considerable effort. It is unfortunate that no one was able to answer this in time. Perhaps you people want some monetary compensation? Or maybe no one liked my problem. Not particularly hard, is it?- james brug
- Post #2
- Forum: Introductory Physics Homework Help
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How Is Total Work Calculated for Two Connected Blocks with Friction?
Homework Statement Two blocks are connected by a very light string passing over a massless and frictionless pulley . The 20.0 N block moves 75.0 cm to the right and the 12.0 N block moves 75.0 cm downward. Find the total work done on the 20 N block if \mu _s\;=(coeff. of static...- james brug
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- Blocks Two blocks Work
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- Forum: Introductory Physics Homework Help
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Calculating Work in a Pulley System
What about the work done on the other block? Is it the same?- james brug
- Post #10
- Forum: Introductory Physics Homework Help
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Calculating Work in a Pulley System
What first statement?- james brug
- Post #8
- Forum: Introductory Physics Homework Help
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Calculating Work in a Pulley System
T would give me the force on the 20N block and thus the work, yes? a=12N/total weight?- james brug
- Post #6
- Forum: Introductory Physics Homework Help
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Calculating Work in a Pulley System
That's probably it. There is a problem nearly identical to this in the book, but it says the blocks are moving at a constant speed.- james brug
- Post #4
- Forum: Introductory Physics Homework Help
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Calculating Work in a Pulley System
Work problem--blocks,pulley Homework Statement Two blocks are connected by a very light string passing over a massless and frictionless pulley . The 20.0 N block moves 75.0 cm to the right and the 12.0 N block moves 75.0 cm downward. Find the total work done on 20.0N block if there is...- james brug
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- Work
- Replies: 11
- Forum: Introductory Physics Homework Help