Recent content by jamesbob

  1. J

    Why are integrals well defined?

    Yeah, thanks. Its just the way my silly university asks questions and explains things that confused me. Thanks for the help :smile:
  2. J

    Why are integrals well defined?

    Im having trouble explaining why intergrals are well defined. For instance: \int_{0}^{\infty} \frac{1}{(x + 16)^{\frac{5}{4}}}dx. Here do i say something like: \mbox{The integral behaves at zero, and at } \infty, (x + 16)^{\frac{5}{4}} > x^{\frac{5}{4}} \mbox{ therefore the integral diverges.}
  3. J

    What is the partial derivative of u with respect to t in terms of x, y, and t?

    Yeah, realized that after some research - just something id never saw. Dead easy tho. Thanks anyway :smile:
  4. J

    What is the partial derivative of u with respect to t in terms of x, y, and t?

    This is annoying me as i have the answer on the tip of my pen, just can't write it down. I'm not 100% sure i understand what the question is asking me to do. Consider the quantity u = e^{-xy} where (x,y) moves in time t along a path: x = \cosh{t}, \mbox{ } y = \sinh{t} Use a method...
  5. J

    How Do You Solve the Homogeneous Part of Second Order Differential Equations?

    Another example of this question type that I am stuck on is: \ddot{x} + 7\dot{x} + 12x = 24 Find the particular solution where x(0) = 3, \left \dot{x}(0) = -2 My working is: Homogeneous: For this we read off the characteristic quadratic: \lambda^2 + 7\lambda + 12 = 0 Find...
  6. J

    How Do You Solve the Homogeneous Part of Second Order Differential Equations?

    Ah rite i see how that works. If i get two solutions for lambda, is my complimentary function: Ae^{\lambda_1} + Be^{\lambda_2} or Ae^{\lambda_1 + \lambda_2} ?
  7. J

    How Do You Solve the Homogeneous Part of Second Order Differential Equations?

    I found a similar question in a past paper that has solutions and from it learned things about the characteristic equation you mentioned, and also to use A + B. This question is: \ddot{x} + 4\dot{x} + 5x = 34e^{2t} You get the characteristic quadratic: \lambda^2 + 4\lambda + 5 = 0 So...
  8. J

    How Do You Solve the Homogeneous Part of Second Order Differential Equations?

    \ddot{x} + 10\dot{x} + 34x = 50e^{-t} Im stuck on getting the homogeneous equation. I am used to equations with just first derivatives, not second derivatives as well. Usually, i'd set the left hand side equal to zero and say: set \left x = Ae^{\lambda{t}} \left and \left so \left \dot{x} =...
  9. J

    Differencing x/4: What is the Rule?

    I'd already worked this out but thanks for that explanation - I am sure it'l help in the future. I am revising for exams - it was just a silly hurdle in a question - so no, not homework. Thanks again:smile:
  10. J

    Differencing x/4: What is the Rule?

    Im unsure on a very very basic differetiation i need for part of a question. Quite simply - differentiate x/4. Thats it. Or x over any number - just never knew the rule. Is it simply 1? or 4? or 1/4? I need to know for a question where iv to find the differential du for u = sin(x/y)...
  11. J

    Calculating Mass of Spherical Planet: Solve Confusing Question

    ok thanks, and that will be the answer because by intergrating i find the sum of all the smaller parts?
  12. J

    Calculating Mass of Spherical Planet: Solve Confusing Question

    Question: A spehrical planet of Radius R has a density p which depends on the distance r from its centre according to the formula p = \frac{p_0}{1 + (r/R)^2} where p_0 is a constant. By dividing the planet up into spherical shells of a small thickness dr, find the mass of the planet...
  13. J

    Well Defined Integrals: Proving and Evaluating with Domain Restrictions

    Here iv to show that integrals are well defined and find their values: a) I = \left\int_{0}{4} \frac{x - 1}{\sqrt{16 - x^2}}dx this one i can show its well defined ok (the domain will be positive as x will be between 0 and 4) but can't find the value. So far my work goes: I =...
  14. J

    Interesting rate of change question

    Ah sorry, of course! I was tired, wasn't thinking straight. Hand in time has passed now, but i was determined to get to the bottom of this. I can see now how to do it. Thanks very much!
  15. J

    Interesting rate of change question

    But using the product rule isn't it just: u = -2ab, du/dt = 0 v = cosC dv/dt = -sinC giving udv/dt = vdu/dt = -2ab-sinC + cosC.0 = 2absinC? Using this i have \frac{dc^2}{dt} = 2a\frac{da}{dt} + 2b\frac{db}{dt} + 2ab\sin C = 2 \times 5 \times 2 + 2 \times 10 \times 1 + 2...
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