Recent content by jan2905

1/3? 3m*(1/9)v^2 yields a factor of 1/3.

You will have to use your imagination: 3 tracks are constructed as such... path 1 (P1) is similar to a "down-facing parabola," path 2 (P2) is straight, and path 3 (P3) is similar to an "up-facing parabola." P1 is "uphill," P2 is "through that hill," and P3 "under the hill, beneath P2, and...

An object of mass m (O1) moving with speed v collides head-on with a target object of mass 2m (O2) initially at rest. If the collision is perfectly inelastic, what fraction of O1's initial kinetic energy is lost? 1/2(m1)v^2initial=1/2(m1+m2)v^2final m1v1=(m+2m)v2 v2=1/3(v1)...

A solid plastic cube with uniform density (side length = 0.5m) of mass 100kg is placed in a vat of fluid whose specific gravity is 1.2. What fraction of the cube's volume floats above the surface of the fluid? I couldn't figure this one out. I tried using the ration of SG's.

you said it wasn't 200N... because it's 196N? ... sorry I rounded.

but we deduced that p1 would have more pressure therefore hurting more. this math seems to be counterintuitive.

how can that be? F=mg=30kg(2/3)(9.81)=196...

would this mean that if i were hit with the liquid at the respective points... p1 would hurt more than p2? that would mean that a large mouth waterhose has more force than a small mouth... that is not correct though.

yes 3 is the same on both posts: 3 (first post): the switch is opened, and the dielectric removed. 3 (last post): capacitor no longer charging [the switch is opened] and dielectric is removed I am restating my logic. Is this correct? Anyone! delta=final-initial; numerals correspond...

This problem doesn't require integration. and... how did you derive V = (F*d)/q? if F=Eq, then by your derivation V=(Eq)*d/q, which is reduced to V=Ed? how does V=Eqd=Ed?

is specific gravity (rho)?

Okay... R is increased. So, II only because V is constant throughout and R is increased therefore, I decreases. More heat is generated because R is increased, therefore III is not an answer... power dissipation is in the form of heat. I is not an answer because V is constant. Correct?

An object with mass 30kg and specific gravity 3.6 is placed in a fluid whose specific gravity is 1.2. Neglecting viscosity, what is the objects acceleration and weight? I guessed on this one. Not sure how to make things come together. I said that a=2/3(g) and F=200N

A fluid of density (rho) flows through a horizontal pipe with negligible viscosity. The flow is streamline with constant flow rate. The diameter of the pipe at Point 1 is d and the flow speed is v. If the diameter of the pipe at Point 2 is d/3, then the pressure at Point 2 is...

I don't know... V=Eq*d ? because F=Eq ?