Perfectly Inelastic and initial kinetic energy

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In a perfectly inelastic collision between two objects, one of mass m moving at speed v collides with a stationary object of mass 2m. The final velocity of the combined mass after the collision is calculated to be v/3. The initial kinetic energy of the moving object is 1/2(m)v^2, while the final kinetic energy of the combined mass is 1/2(3m)(1/3v)^2, which simplifies to 1/9(m)v^2. This indicates that the fraction of O1's initial kinetic energy lost in the collision is 2/3. The calculations confirm that the energy loss is consistent with the principles of momentum and energy conservation in inelastic collisions.
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An object of mass m (O1) moving with speed v collides head-on with a target object of mass 2m (O2) initially at rest. If the collision is perfectly inelastic, what fraction of O1's initial kinetic energy is lost?



1/2(m1)v^2initial=1/2(m1+m2)v^2final

m1v1=(m+2m)v2

v2=1/3(v1)

so...

1/2(m1)v^2=1/2(m1+m2)(1/3*v)^2 ... is this right so far?
 
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Take the ratio of the final kinetic energy to the initial kinetic energy. These two are not equal to each other unless you include a ratio factor on the left side of the equation.
 
1/3? 3m*(1/9)v^2 yields a factor of 1/3.
 
Correct.
 
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