ok everything makes sense now.
i substituted the equation and came up to
dy=(v^2cos(theta)^2)/g) - (vcos(theta)/2)
Have i done this right so far? if so, how can i continue?
1. I am trying to derive the equation for maximum height of a trajectory. Must be in terms of v, theta, and g.
2.Vy=vsin(theta) dy=vsin(theta)t+0.5gt^2
3. I know that I must find the point when the vertical velocity is equal to zero and must find one equation for time. Then sub this...
This is what I have wrote so far, i just need to know if i am generally correct in my physics terms, keep in mind that this is a simplistic grade 10 course...
Can someone please help me in describing the physics surrounding a mid-ice check. I am using Chara(118kg, 10m/s) hitting Crosby(87kg, 0m/s).
I just need to know the mechanics(forces and energy) without using very complicated terms.