Recent content by javacola

  1. J

    U-Substitution in Calculus: Solving a Difficult Integration Problem

    I told you I don't know much about calculus...so just saying "come on" isn't going to magically help me get the answer. Is u x^7? Or 4-3x^16?
  2. J

    U-Substitution in Calculus: Solving a Difficult Integration Problem

    Homework Statement 1~~0 (x^7)/sqrt(4-3x^16) dx The Attempt at a Solution There really isn't one. I am as clueless as one can get in calculus. I know that I am supposed to substitute the variable "u" in for a section of this problem, but really don't know anything after that. I...
  3. J

    How Do You Calculate the Tension in a String of a Suspended Charged Cork Ball?

    Homework Statement A charged cork ball of mass m is suspended on a light string in the presence of a uniform electric field, as shown in the figure below. When E = (Ai + Bj) N/C, where A and B are positive numbers, the ball is in equilibrium at the angle ?. b) Find the tension in the...
  4. J

    Marianas Trench Homework: Volume & Density Calcs

    Thanks a lot guys. Got it with 3 minutes to spare. Have no clue how you knew initial volume was 1, that's what threw me off.
  5. J

    Marianas Trench Homework: Volume & Density Calcs

    My first instant was that since mass is negligent, the change in volume should equal the change in density. But that doesn't seem to be working.
  6. J

    Marianas Trench Homework: Volume & Density Calcs

    Alright well let's see. mass divided by initial volume is 1030. mass divided by initial volume + delta volume = the density I'm looking for. Is this the right track?
  7. J

    Marianas Trench Homework: Volume & Density Calcs

    Homework Statement In the Challenger Deep of the Marianas Trench, the depth of seawater is 10.9 km and the pressure is 1.16x10^8 Pa (about 1.15x10^3 atm. A) If a cubic meter of water is taken from the surface to this depth, what is the change in its volume? (Normal atmospheric pressure is...
  8. J

    What is the average force on a baseball after being hit by a bat?

    Same thing basically. 34.4146 (vertical component of velocity) = 50 + a (0.00165) a= -9445.69697 Fy= (-9445.69697)(.145) Fy= -1369.626= -1400 (sig figs)
  9. J

    What is the average force on a baseball after being hit by a bat?

    Thanks, I got the first part. But the same thing isn't working for the second. It isn't negative since it's going up. Do I need to factor in gravity somehow?
  10. J

    What is the average force on a baseball after being hit by a bat?

    Ok, did that and still got it wrong. Spitting 60 into components I get: Fx= 49.15 and Fy= 34.4146 Now plugging in: 49.15 = 50 + a(0.00165) a= -515.15 Fx= (.145)(-515.15) Fx= 74.69 = 75 (sig figs) Wrong still.
  11. J

    What is the average force on a baseball after being hit by a bat?

    Homework Statement A bat strikes a 0.145 kg baseball. Just before impact, the ball is traveling horizontally to the right at 50.0 m/s, and it leaves the bat traveling to the left at an angle of 35 degrees above horizontal with a speed of 60.0 m/s. The ball and bat are in contact for 1.65...
  12. J

    What is the Coefficient of Kinetic Friction on a Horizontal Surface?

    Homework Statement In a truck-loading station at a post office, a small 0.200 kg package is released from rest at point A on a track that is one-quarter of a circle with radius 1.60 m (the figure ). The size of the package is much less than 1.60 m, so the package can be treated as a particle...
  13. J

    Force of Particle at x=-0.660 m | Alpha = 1.50 J/m^4

    Homework Statement A force parallel to the x-axis acts on a particle moving along the x-axis. This force produces a potential energy U(x) given by U(x)= alpha x^4 where alpha=1.50 J/m^4. What is the force when the particle is at position x = -0.660 m? Homework Equations The...
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