Recent content by javacola

  1. J

    U-Substitution in Calculus: Solving a Difficult Integration Problem

    I told you I don't know much about calculus...so just saying "come on" isn't going to magically help me get the answer. Is u x^7? Or 4-3x^16?
  2. J

    U-Substitution in Calculus: Solving a Difficult Integration Problem

    Homework Statement 1~~0 (x^7)/sqrt(4-3x^16) dx The Attempt at a Solution There really isn't one. I am as clueless as one can get in calculus. I know that I am supposed to substitute the variable "u" in for a section of this problem, but really don't know anything after that. I...
  3. J

    How Do You Calculate the Tension in a String of a Suspended Charged Cork Ball?

    Homework Statement A charged cork ball of mass m is suspended on a light string in the presence of a uniform electric field, as shown in the figure below. When E = (Ai + Bj) N/C, where A and B are positive numbers, the ball is in equilibrium at the angle ?. b) Find the tension in the...
  4. J

    Volume and density change of seawater at Challenger Deep

    Thanks a lot guys. Got it with 3 minutes to spare. Have no clue how you knew initial volume was 1, that's what threw me off.
  5. J

    Volume and density change of seawater at Challenger Deep

    My first instant was that since mass is negligent, the change in volume should equal the change in density. But that doesn't seem to be working.
  6. J

    Volume and density change of seawater at Challenger Deep

    Alright well let's see. mass divided by initial volume is 1030. mass divided by initial volume + delta volume = the density I'm looking for. Is this the right track?
  7. J

    Volume and density change of seawater at Challenger Deep

    Homework Statement In the Challenger Deep of the Marianas Trench, the depth of seawater is 10.9 km and the pressure is 1.16x10^8 Pa (about 1.15x10^3 atm. A) If a cubic meter of water is taken from the surface to this depth, what is the change in its volume? (Normal atmospheric pressure is...
  8. J

    What is the average force on a baseball after being hit by a bat?

    Same thing basically. 34.4146 (vertical component of velocity) = 50 + a (0.00165) a= -9445.69697 Fy= (-9445.69697)(.145) Fy= -1369.626= -1400 (sig figs)
  9. J

    What is the average force on a baseball after being hit by a bat?

    Thanks, I got the first part. But the same thing isn't working for the second. It isn't negative since it's going up. Do I need to factor in gravity somehow?
  10. J

    What is the average force on a baseball after being hit by a bat?

    Ok, did that and still got it wrong. Spitting 60 into components I get: Fx= 49.15 and Fy= 34.4146 Now plugging in: 49.15 = 50 + a(0.00165) a= -515.15 Fx= (.145)(-515.15) Fx= 74.69 = 75 (sig figs) Wrong still.
  11. J

    What is the average force on a baseball after being hit by a bat?

    Homework Statement A bat strikes a 0.145 kg baseball. Just before impact, the ball is traveling horizontally to the right at 50.0 m/s, and it leaves the bat traveling to the left at an angle of 35 degrees above horizontal with a speed of 60.0 m/s. The ball and bat are in contact for 1.65...
  12. J

    What is the Coefficient of Kinetic Friction on a Horizontal Surface?

    Homework Statement In a truck-loading station at a post office, a small 0.200 kg package is released from rest at point A on a track that is one-quarter of a circle with radius 1.60 m (the figure ). The size of the package is much less than 1.60 m, so the package can be treated as a particle...
  13. J

    Finding force from potential energy U(x) = αx⁴ at x = -0.660 m

    Homework Statement A force parallel to the x-axis acts on a particle moving along the x-axis. This force produces a potential energy U(x) given by U(x)= alpha x^4 where alpha=1.50 J/m^4. What is the force when the particle is at position x = -0.660 m? Homework Equations The...