Recent content by JBemp

yes but i was thinking what stops me from making a pump so large the i can pump anyways

Hiya my question is Why is it impossible with a pump to suck water from a lake if you place the pump 15 meters above the water I think it has somthing to do with gravity but if anyone could explain it in detail that would be great Thanks :)

Somewhere along the way i missed the diffrence between m/s and m/s^2 can someone please explain to me when i should use one or the other. i know there is some way to see it while working out the problem but is there any general rules or tips one could use as a guide line, my instructor say we...

Homework Statement A ball is thrown stright up with the speed 25m/s how high does the ball go? Homework Equations S=v*t or V=vot+at I know gravity is a neg acceloration so I should have -9.81 somewhere The Attempt at a Solution I need to find the time first am guessing so, T=s/v...

ok i see what i did worng forgot the darn ( ) on the calc. man these ( ) always screw me. thank you both

Homework Statement what is the frequecy F for the alterating current U(T)=15cos(314t) A Homework Equations Am really new at this kind of problem but i think 314 is how many times the current rotates or fluxuates in 1 period so the F has to be the distance between waves? The...

Homework Statement find the linear fuction ( in swedish its called the riktningskoefficient i think ,dunno if there the same thing am taking the text from a swedish book and translating to english) for the stright line 3x-15y+7=0 Homework Equations Am unsure on how to proceed but I think...

Been checking the net and found that for a uniform shape i should just do H/2 so (60+6)/2 = 33m so the (cg) is 33m from the bottom of the T shape?

Homework Statement Center of gravity for a shape T both arm are 60mm long and 6mm wide. Homework Equations dont know the equation but seeing as there is not wieght involved am guessing the formula isn't that hard. a discription of the formula and how to use it would help alot...

ok am even worse at square roots then i am at algebra but here we go. d=\sqrt{1*2} =1.41 {d^2}=\sqrt{1} =1 setting them equal d+1.41={d^2}+1 then i try to solve d by setting the problem = 0 0={d^2}-0.41-d am i on the right track or did i screw it up agian?

am a little unsure on how to get a root out of a fraction like this when i have (1-d)^2 {0} = {\sqrt{\frac{2}{(1-d)^2} or {0} = {\sqrt{\frac{2}{1-2d+d^2} or somthing like this i know they both say the same thing i just don't know what to do with the d's. if i plug {0} =...

\frac{2}{(1-d)^2} = \frac{1}{d^2} ok dident know you move the 2 and the 1 up onto the fraction \frac{2}{1-2d+d^2} = \frac{1}{d^2} \frac{2-1}{1-2d} \frac{1}{1-2d} am i getting near?

ok so then somthing like this? q^2/d^2 = q^2/d^2 is = 0 so turning (1-d)^2 into 1-2d+d^2 was the right thing to do? but unsure about 2k/k that should only leave k? or 2? 2={1-2d} i get that -0.5

can i just cancel them out like this 2K\frac{Q^2}{(1-d)^2} = {k \frac{Q^2}{d^2} {k=1-2d} I guess i need to asign k a value? 8.99*10^9 but that number is huge 8990000000 {8990000000=1-2d} (this has to be wrong but i don't know what else to do) {2d=1-8990000000} or do i...

ok here i go agian am trying to set them equal, i know this is algebra but i have always been really bad at algebra F_{2Q} = k \frac{2.00 C*1.00 C}{1-d^2} F_{Q} = k \frac{1.00 C*1.00C}{d^2} F_{2Q}=\frac {2.00 C*1.00 C}{1-d^2} F_{Q}=\frac {1.00 C*1.00 C}{d^2} F_{2Q}=\frac...