What is the Frequency of an Alternating Current with a Sin Curve?

AI Thread Summary
The frequency of the alternating current described by the equation U(T) = 15cos(314t) can be calculated using the formula F = ω/(2π), where ω is the angular frequency. In this case, ω is 314, leading to a frequency calculation of 314/(2π), which equals approximately 49.89 Hz. A misunderstanding occurred regarding the calculation process, where the user initially misapplied the formula. After clarification, the correct approach was confirmed, emphasizing the importance of proper use of parentheses in calculations. Accurate frequency determination is essential for understanding the behavior of alternating currents.
JBemp
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Homework Statement


what is the frequecy F for the alterating current
U(T)=15cos(314t) A


Homework Equations


Am really new at this kind of problem but i think 314 is how many times the current rotates or fluxuates in 1 period so the F has to be the distance between waves?



The Attempt at a Solution



15cos(314T)

314/2pi i get 493.23 but i know that's wrong
 
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Are you sure 314/(2pi) is 493.23? Check with your calculator properly :wink:
 
Last edited:
U\propto cos(\omega t) ~~~~ \omega = 2\pi \nu

So you should divide 314 with 2pi, not divide 314 with 2 and then multiply with pi.
 
ok i see what i did worng forgot the darn ( ) on the calc. man these ( ) always screw me.

thank you both
 

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