Recent content by jeahomgrajan

what are the x and y intercepts y= x+2/x-7 rational expression is y=-2/7 and x= -2

i think I've figured it out, so basically i would divide both sides by -2, and when i divide and an equality by a -, i will hav eot change the direction of the sign

Homework Statement determine the interval algebraically for -2(x-1)(2x+5)(x-7)>0 The Attempt at a Solution the zeroes are 1. -2.5, 7 what do i do with the -2 in front?

i believe i have to get ride of the -2/3 how will i do so? ( i am trying to graph it so i should be able to apply the transformations)

it is stated that i have begun doing that, so now i know i will have to divide -2/3 by x+5/3, then i will sqareroot the left side, as the right side is being squared, and the finally bring over the 5 which will reslut in -5 overall equation = (sqareroot)(x+5/3) - 5 =y ....... -2/3...

what is the inverse of f(x)=-2/3(x+5)^2 - 5/3 so far i got x=-2/3(y+5)^2 -5/3 bring 5/3 over to x side x+5/3=-2/3(y+5)^2 although i know what to do, can someone just explain how they will go on from here

Alright i understand thanks

y= SqaUREROOT 25-x^2, (this should be a semicircle right?

intence, but okay, what about the second equation which i have mentioned

+-3?

y=5-x

Homework Statement This is a simple math equation and i am a bit confused on how x^2+y^2=25 makes a circle and how y= sqrt 25-x^2 makes a semi circle

How do i find the pH of FeSO4(s), knowing that its concentration is 0.10mol/L it is a salt.. and it was placed in distilled water..FeSO4---->< Fe+2 + SO4-2 SO4-2 is the conjugate base of a strong acid H2SO4- therefore SO4-2 has no effect on the pH in this case what is Fe+2,would be an acid...

In this case what method would you use...

alright suppose you do titration , which acid can you use?and why