Finding the Interval for -2(x-1)(2x+5)(x-7) > 0

  • Thread starter Thread starter jeahomgrajan
  • Start date Start date
  • Tags Tags
    Interval
AI Thread Summary
To solve the inequality -2(x-1)(2x+5)(x-7) > 0, the zeroes are identified as -2.5, 1, and 7. The negative coefficient in front of the expression indicates that the function's sign will flip when multiplied by -2. Analyzing intervals shows that the function is positive for x < -2.5 and between 1 and 7, while it is negative between -2.5 and 1, and for x > 7. Therefore, the solution to the inequality is the intervals (-∞, -2.5) and (1, 7).
jeahomgrajan
Messages
49
Reaction score
0

Homework Statement


determine the interval algebraically for -2(x-1)(2x+5)(x-7)>0



The Attempt at a Solution


the zeroes are 1. -2.5, 7

what do i do with the -2 in front?
 
Physics news on Phys.org
If you graph y=(x-1)(2x+5)(x-7) and then multiply the function by 2, so now you have the graph y=2(x-1)(2x+5)(x-7) and finally, take the negative.

Now do you know what y=-2(x-1)(2x+5)(x-7) looks like?
 
i think I've figured it out, so basically i would divide both sides by -2, and when i divide and an equality by a -, i will hav eot change the direction of the sign
 
Yes you can do that too. But understanding what happens to the function when you multiply it by a negative constant would be a useful tool to have in your arsenal :wink:
 
As you say, the zeroes are -2.5, 1, and 7. Suppose x< -2.5. Then each of the factors is negative. Since there are 4 factors, counting the '-2', there product, and the function value, is positive. Now take x between -2.5 and 1. The single factor (2x+ 5)= -2(x- 2.5) changes sign so there are now three negative factors: the function value is negative between -2.5 and 1. Take x between 1 and 7. Now the x-1 factor changes sign to postive and there are now 2 negative factors: the function value is positive between 1 and 7. Finally, if x> 7, all factors except the '-2' are positive: for x> 7, the function value is negative.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top