Recent content by jeff12

Can you give me an example of it not going opposite of the motion of the object?

It is because when my professor he explained it using two blocks, the big one on the bottom and a small on top and he said the static friction was moving in the direction the objects were moving.

Can someone please explain me the direction of static friction? I know kinetic friction is always going against the motion of an object but for static friction it depends.

Why is Fg positive for m2 Fg? Can you draw it out on the whiteboard which sign should be where?

So if to the right of M1, which is on the x-axis to the right was positive then the M2 going up would be positive too?

So how would you define it? Which part of my signs is wrong?

Why are all forces positive? That doesn't sound right.

Homework Statement A block of mass m1 = 3.70 kg on a frictionless inclined plane of angle 30.0° is connected by a cord over a massless, frictionless pulley to a second block of mass m2= 2.30 kg hanging vertically. What are (a) the magnitude of the acceleration of each block and (b) the...

There was no C. I figured that out. I was confused because in his example he kept saying R=A+B+C. But since I was only given two vectors it would be R=A+B. I found R=14.75i+42.07j. The magnitude is 44.58 mi at 70.68^o.

Oh I fixed it. I think I understand everything now. But I want to make sure, C is the resultant right? Because C is technically R. Yes because that would change the problem entirely.

Okay, R=(-1.48)i+(2.61)j Magnitude: R=2.99 but what is the direction? Is that right? I just want to clarify the R that we found is considered the F4 but found mathematically right? Because in the lab we were given F1, F2, ,F3 and we had to find F4 using the weights.

Is the formula: R=A+B+C which would be R=(F1x+F1y)i+(F2x+F2y)j+(F3x+F3y)k?

Homework Statement This is the force table lab that we are doing. F _1 = 300g @ 30^o F _2 = 450g @ 110^o F _3 = 400g @ 230^o F _4 = 270g @ 298^o Finding resultant force using Component Method 1. Express each force F1, F2, and F3 in unit vector notation. Take the origin to be at the center...

Bump.

Okay I redid everything and found: A=20cos60i+20sin60j B=35cos45i+35sin45j C=(-20cos60+35cos45)i+(20sin60+35sin45)j Did I do all the trig stuff right? I am suppose to find the magnitude too which I found was 97.62.