Recent content by jfhorns7853

Awesome!

Oh, I wasn't saying that I was going to use this on my calculator. I was just trying to give some sort of example to the level of experience that have with programming.

My bad, yes f(8) is right.

Lastly, your f(5) and f(8) values ARE WRONG. Make sure that you plugged 5 and 8 into f(x) and nothing else. Also, upon graphing, you will note that f(8) is not an absolute max or min. Compare f(0), f(5), and f(8)

btw, you're x-values are right, but your process is flawed. Also, b/c of the interval, only f(5) applies from the derivative. You will also want to graph the equation to make sure. Graph all of f(x) and then eyeball where 0 and 8 are and just mark through them to show exactly the part of the...

You can't cancel {-x^2+25} and {(x^2+25)^2} b/c of the negative. If you factor out the negative: \frac{-(x^2-25)}{(x^2+25)^2} Which gives you a numerator of {-(x+5)(x-5)} which are your zeros of f'(x) and you just plug those x-values of x = +/- 5 into f(x) and find your max and min.

Alright cool guys. Thanks! I think I'll start with that 3rd link, TurtleMeister.

This is more or less just a hobby. I'm not looking for anything too serious. I guess that I should have mentioned that... >_<

Umm... Do I need to go out and buy anything or what...?

[SIZE="3"][FONT="Times New Roman"]I am looking to start learning programming more or less on my own. I can make some advanced programs on the TI-83+ calculator and have been for the past year. I learned just from reading the manual and messing with the different logic operators and commands...

haha Sorry to leave out the fairer side of the math nerds or really nerds in general! haha so yeah, The second way makes more sense I think.

This is a question from a TI-83/84 calculator exam that I took on February 14th. (haha what a shocker a math nerd without a girlfriend.) Anyway, this is one of the few that I missed, and when I revisited it I noticed that I had actually misread the question at hand. Anyway, the problem is that...