Recent content by jimen113

thanks.

omg...thank you for your help... I did try plugging in (-2) and I end up with: 1+B(12)+1+D(36)+3=1 and B(12)+D(36)=-4 so I'm still left with the two unknowns...

Thank you so much for your help zcd and cyosis. Last question: I get A= (1/9) C=(-1/4) E=(-1/12) But to find D and B I tried plugging in zero and didn't get anywhere. What other numbers can I plug into solve for D and E? :blushing:

Homework Statement use the method of partial fractions on \int \frac{36}{(x-2)(x-1)^2(x+1)^2} dx [b]2. Homework Equations [b]3. The Attempt at a Solution \frac{A}{(x-2)} + \frac{B}{(x-1)} + \frac{C}{(x-1)^2} + \frac{D}{(x+1)} + \frac{E}{(x+1)^2} I took the 36 out of the...

1. Homework Statement [/b] Sketch the region bounded by the curves, and visually estimate the location of the centroid. Then find the exact coordinates of the centroid: Homework Equations I don't have the answer for this problem to check my work. The Attempt at a Solution see...

Thanks Mark44! that negative sign is sure important...:redface:

Thank you HallsofIvy for your help. Yes it did forget! but wouldn't by dx= sin \vartheta please see the updted the attachment.

I tried to use the latex reference but it was way too complicated for me. Can you see the attachment. Thank you!

Can you please verify my work: (3) (Q3/5)+Q3 \rightarrow 6Q3/5 (1) (6Q3/5) +Q2 v=(Q1/3) +Q2 Q2=(V)(3/Q1) Q2=(Q1/3 + Q2 )(3/Q1)\rightarrow3Q1+3Q2/(3Q1)\rightarrow{3Q1+3(Q3/5)} /(3Q1) \rightarrow Q2=(7/6) *v=(Q1/3) +Q2 v=(6Q3)/5 +(7/6)\rightarrow Q3=35/6 so then Q1= 6Q3/5 \rightarrow...

I think you're right... I just don't know how to set up the solution to finding the individual charges: Q1=C (Q1/3c +Q2)? I can't solve for Q1 the answer to thi problem is: Q1>Q3>Q2

sorry...I guess I'm a little slow.. so.. do you mean the charge (Q2 is equal to (Q3/5) or that the voltage on C2=Q3/5?

Yes, I think I am wrong there too. I see how c4 is the combination opf c2 and c3.

Homework Statement Three capacitors are connected to a battery as shown. Their capacitances are c1=3C c2=C c3=5C -------c1---------------------- |......|...| |......|...| V......c2-----------c3 |_______________|__________| Homework Equations state the ranking of the capacitors...

Thank you!

Solved! {(8.99x10^9)(-7.50x10^-6)}/ (.14/pi)= -1513013.461= -1.51MV