jimen113 Messages 66 Reaction score 0 Thread starter Feb 26, 2009 #1 I tried to use the latex reference but it was way too complicated for me. Can you see the attachment. Thank you! Attachments 7-3 problem 2.gif 1.9 KB · Views: 552
I tried to use the latex reference but it was way too complicated for me. Can you see the attachment. Thank you!
HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 983 Feb 26, 2009 #2 If you are letting [itex]x= cos(\theta)[/itex] then [itex]dx= cos(\theta)d\theta[/itex]. It looks to me like you forgot that [itex]cos(\theta)[/itex].
If you are letting [itex]x= cos(\theta)[/itex] then [itex]dx= cos(\theta)d\theta[/itex]. It looks to me like you forgot that [itex]cos(\theta)[/itex].
jimen113 Messages 66 Reaction score 0 Feb 26, 2009 #3 Thank you HallsofIvy for your help. Yes it did forget! but wouldn't by dx= sin [tex]\vartheta[/tex] please see the updted the attachment. Attachments 7-3 problem 2 updated.gif 3.4 KB · Views: 556
Thank you HallsofIvy for your help. Yes it did forget! but wouldn't by dx= sin [tex]\vartheta[/tex] please see the updted the attachment.
Mark44 Mentor Insights Author Messages 38,144 Reaction score 10,741 Feb 26, 2009 #4 If x = cos([itex]\theta[/itex]), then dx = -sin([itex]\theta[/itex])d[itex]\theta[/itex]
HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 983 Feb 26, 2009 #5 Yes, of course Mark44 is right. I don't know what came over me!
jimen113 Messages 66 Reaction score 0 Feb 26, 2009 #6 Thanks Mark44! that negative sign is sure important...