Feb 26, 2009 #1 jimen113 Messages 66 Reaction score 0 I tried to use the latex reference but it was way too complicated for me. Can you see the attachment. Thank you! Attachments 7-3 problem 2.gif 1.9 KB · Views: 548
I tried to use the latex reference but it was way too complicated for me. Can you see the attachment. Thank you!
Feb 26, 2009 #2 HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 983 If you are letting [itex]x= cos(\theta)[/itex] then [itex]dx= cos(\theta)d\theta[/itex]. It looks to me like you forgot that [itex]cos(\theta)[/itex].
If you are letting [itex]x= cos(\theta)[/itex] then [itex]dx= cos(\theta)d\theta[/itex]. It looks to me like you forgot that [itex]cos(\theta)[/itex].
Feb 26, 2009 #3 jimen113 Messages 66 Reaction score 0 Thank you HallsofIvy for your help. Yes it did forget! but wouldn't by dx= sin [tex]\vartheta[/tex] please see the updted the attachment. Attachments 7-3 problem 2 updated.gif 3.4 KB · Views: 552
Thank you HallsofIvy for your help. Yes it did forget! but wouldn't by dx= sin [tex]\vartheta[/tex] please see the updted the attachment.
Feb 26, 2009 #4 Mark44 Mentor Insights Author Messages 38,138 Reaction score 10,719 If x = cos([itex]\theta[/itex]), then dx = -sin([itex]\theta[/itex])d[itex]\theta[/itex]
Feb 26, 2009 #5 HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 983 Yes, of course Mark44 is right. I don't know what came over me!
Feb 26, 2009 #6 jimen113 Messages 66 Reaction score 0 Thanks Mark44! that negative sign is sure important...