Recent content by jkface

  1. J

    Inverse Fourier Transform of cos(4ω + pi/3)

    Homework Statement Find the inverse Fourier transform of F(jω) = cos(4ω + pi/3)Homework Equations δ(t) <--> 1 δ(t - to) <--> exp(-j*ωo*t) cos(x) = 1/2 (exp(jx) + exp(-jx))The Attempt at a Solution So first I turned the given equation into its complex form using Euler's Formula. F(jω) = 1/2...
  2. J

    Fraction Simplification: Solving Equations with Constants C, L, and R

    i(s) = V2(s)(1+sCR) / sL + (V2(s)(1+sCR) - V2(s)) / R i(s) = V2(s)( (1+sCR) / sL + sCR / R) V2(s) = i(s) (sL / (1+sCR) + 1 / sC) = i(s) ((s^2 * LC + 1 + sCR) / sC(1+sCR)) V2(s) = i(s) ((s^2 * LC + 1 + sCR) / (sC+s^2 * C^2 * R)) this is obviously not what I'm supposed to have.
  3. J

    Fraction Simplification: Solving Equations with Constants C, L, and R

    I have the following two equations C, L, and R are all constants. I need to somehow get the above two equations and get it to look like this: But I can't get mine to look that nice. I have V1(s) = V2(s)(1+sCR) and I substituded it into equation 1 and it ends up looking messy...
  4. J

    Is f(x) = cos^2(x) + sin^2(x) a periodic function?

    Homework Statement Is f(x) = cos^2(x) + sin^2(x) a periodic function? Homework Equations sin^2(x) + cos^2(x) = 1 The Attempt at a Solution This question is just something that randomly came to my mind (not a homework problem). I know cos^2(x) and sin^2(x) are both periodic...
  5. J

    Find the average power delivered by the voltage source

    The original problem states the voltage source privodes 240∠0° V. Since this is a complex number isn't it the same thing as saying 240cos(wt) V (hence Vm = 240V) ?
  6. J

    Find the average power delivered by the voltage source

    I'm confused. Isn't Vm (not V rms) 240 V?
  7. J

    Find the average power delivered by the voltage source

    I think if you multiply 1/2 to the power equation this approach would be correct. but why do you think I can't get the same answer when I try to solve the problem like how I stated in the problem? Since Average Power = 1/2 Vm*Im*cos(θv - θi), and I = 8 - j8 = 11.3∠-45°, can't I just go...
  8. J

    Find the average power delivered by the voltage source

    Homework Statement Homework Equations P = 1/2 Vm*Im*cos(θv - θi) The Attempt at a Solution First I added all the impedance values to find the total impedance seen by the source. Zt = j10 + (50 || 20 + j10) = 15 +j5 Ω Now since the circuit is not purely resistive, I can't...
  9. J

    When to transform the current source to voltage source?

    Homework Statement Homework Equations The Attempt at a Solution First, I found all the impedance values. (starting from the left) Z1 = 1 / (j * 16E5 * 15E-9) = -j41.67 Z2 = 80 Z3 = 30 Z4 = j * 16E5 * 60E-6 = j96 I then combined Z1 and Z2. Z1 || Z2 = (-j41.67 * 80) /...
  10. J

    Calculating the equivalent inductance of a simulated inductor

    Homework Statement I am asked to find the equivalent resistance of a simulated inductor shown above. We are told not to worry about the simulated inductor circuit. The simulated inductor will be incorporated into a larger circuit as shown below. 2. The attempt at a solution I am really...
  11. J

    DC Circuits - How to Determine a Bulb's Brightness

    Thanks everyone for helping me!
  12. J

    DC Circuits - How to Determine a Bulb's Brightness

    Thank you. I think I'm beginning to understand the problem now. Would I reach the same conclusion if I only discuss voltage differences?
  13. J

    DC Circuits - How to Determine a Bulb's Brightness

    Now that you mention it, I'm beginning to realize how stupid my answer sounds. If I multiply 3V/5R by 2/3, would that be the right answer?
  14. J

    DC Circuits - How to Determine a Bulb's Brightness

    Homework Statement The circuit has identical bulbs and an ideal battery. When bulb D is unscrewed from its socket (the socket remains in its place), what would happen to the brightness of bulb F? Homework Equations V = IR The Attempt at a Solution Since bulb D is unscrewed from it...
  15. J

    Would EE be the right choice for me?

    jsgruszynski, thank you very much for your reply. i now understand much more about what i am about to get into :)
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