Recent content by jmb07

how do i go about solving for q in the equation: (F x r x r)/k = (6.63E-6 -q)(q)

thanks! I think i am having an algebra block though haha. So, (6.63E-6 - q2)(q2) = (Frxr)/k Do i need to use the quadratic equation to solve for q2 or is there a more simple way i am missing?

how would i relate q1 to q2? Like i understand that the two added together is the total charge. Should i say that q2 = (F rxr)/(k x q1) and q1 = 6.63E-6 - q2 I try plugging the relations in but i can't seem to put it all together for some reason

total charge of 6.63E-6 C distributed on 2 metal spheres. When the spheres are 6 cm apart, they each feel a repulsive force of 26.9 N. How much charge is on each sphere?? I know that F=(k x q1 x q2)/(r x r) Im not exactly how to solve for these when i don't know either one of them to solve...

i realized i have to use the work/kinetic energy theorem...i got it! thanks!

oops! so it would be 9 kg?? Even then, the answer would still be incorrect...

A steam engine of 1kg pulls 8 cars of 1kg each. The velocity of the engine is 0m/s initially then gets up to 4m/s in a time of 4 s while moving a distance of 5.3 meters. During that time, the engine takes in 134J of heat. What is the change in internal energy? Ok so i know that: internal...

they are just some constants...but i don't know how to set these to equations equal to each other to start the problem...

uh...i know i could try to convert the 29u to (number of atoms)...but i don't have any molecular weight

Lead rod and glass rod have same length at 20.8 degrees celcius. The lead rod is heated to 53.4 degrees celcius. At what temperature must the glass be heated so they are the same length? I know that (change in L)/Lo = (alpha)(change in Temperature) but I am not sure how to set (change in L...

Average molecular mass of air is 29 u. What is the mass density of air at 1 atm and -50 degrees celsius?? This is what i have so far... V=(NkT)/P so V= [(29u)(1.38E^-23)(-50 + 273)]/ 1 = 8.9 x10^-20 The mass is equal to 29u x (6.022 x 10^23) =1.75 x 10^25 density =m/v so = 1.96 x...

forgot this at the beggining: One winter break, while visiting Scotland's Loch Ness, you stop to tour the ruins of Urquhart

See if you can solve this tough one! (energy and momentum) Castle, which are found on the loch's western shore. A truck carrying barrels passes and, as it does, a sealed barrel and a spare lid fall from the truck and land by the side of the road. The barrel comes to rest at the very top of...

nevermind i got it! thanks!

do i even need to use the height of the object??...if so how?