Recent content by jmcmillian

Thanks for all of your advice. I came to my measured value of R_th by measuring the open circuit DC voltage between the terminals of the black box (V_th) and then measuring short circuit DC current between the terminals of the black box (I_sc) then calculating R_th = (V_th)/(I_sc)...

Thanks for the tip. I've uploaded it: http://www.mountainescapesproperties.com/theveninpf.jpg"

Homework Statement I am trying to find the theoretical Thevenin equivalent resistance for a black box that I used in an experiment. The measured Thevenin equivalent resistance was roughly 4786\Omega. However, I have tried several times to solve the problem, but keep arriving at a theoretical...

Homework Statement Find the equivalent resistance for this simple circuit. (Image Attached) Homework Equations Equivalence Equations In parallel: (1/R1 + 1/R2 + ... +1/Rn)^-1 In parallel (2 Resistors): (R1*R2)/(R1+R2) In Series: R1+R2+...+Rn The Attempt at a Solution This was a much...

Homework Statement Find Vo in the circuit. Image of Circuit Diagram Attached Variables: Vo, Io Given: Current (15 mA) Resistors (300\Omega, 300\Omega, 2k\Omega, 10k\Omega, 200\Omega, 3k\Omega Homework Equations Resistors in Series: Ra+Rb+Rc...+Rn Resistors in Parallel...

hunter, Thanks for the advice. There might have been a slight angle to me holding the rope, resulting in the difference.

Is a difference in .07 when it comes to coefficients of kinetic friction for the same object on the same surface significant? I thought it was, but I have yet to determine a reason why. Below is an explanation of my experiment, as brief as possible...

A particle is moving along a straight line with accelerated motion such that a=-ks, where s is the distance from the starting point and kis the proportionality constant to be determined. For s=2 ft the velocity is 4 ft/s, and for s=3.5 ft, the velocity is 10 ft/s. What is s when the velocity is...

Thank you again for all of your efforts. I really think that it is starting to make sense now. PF has been my backbone this year - my instructor hasn't been very available for help, and gets impatient when you don't understand what he's saying. Having the class at 8am doesn't allow for...

Sorry Astronuc, I did not see this last part until just now. Does this mean that if the force is down and to the right of the pivot point, it is clockwise, whereas if it is up and to the right, it is counterclockwise? As to my objective in all of this, I am trying to find equilibrium...

Just Checking for Understanding: resolving each force into x and y components would be my first order of business. Then, finding the perpendicular distance between the point of which I am pivoting. Thanks for the Toronto Site. it has been helpful. I do have a question about a particular...

Thanks, Astronuc. How is that applied to forces that are simply given horizontal or vertical directions? To determine the moment, is it from the force to the point of the moment (I.e. like from 600N to point A, which would be counterclockwise? Or, are we looking from the point to the force?

so in the case of the diagram given, 600 N would be clockwise from A, T1sin(theta) would be anticlockwise?

thanks for your help. I realize that, but how do I determine which moments are clockwise and which are anticlockwise?

Hi guys, I am having difficulty understanding moments and equilibrium. I have attached a diagram of a sample problem. The red Arrows are T1 resolved into X and Y components. Let's say that I want to find the equilibrium equation for the moments about A and B. I realize that forces...