- #1

jmcmillian

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## Homework Statement

Find Vo in the circuit.

*Image of Circuit Diagram Attached*Variables: Vo, Io

Given: Current (15 mA)

Resistors (300[tex]\Omega[/tex], 300[tex]\Omega[/tex], 2k[tex]\Omega[/tex], 10k[tex]\Omega[/tex], 200[tex]\Omega[/tex], 3k[tex]\Omega[/tex]

## Homework Equations

Resistors in Series: Ra+Rb+Rc...+Rn

Resistors in Parallel: [(1/Ra)+(1/Rb)+(1/Rc)+...+(1/Rn)]^-1

V_j = I_j*R_j; I_j = R_eq*I

## The Attempt at a Solution

I've decided my approach in this problem should be:

(1) Find Equivalent Resistance (R_eq)

(2) Use the formula I_j=R_eq*I to determine I_o

(3) Use I_o to find V_o, as V_o= I_o*R_o

My problem is that I really am unsure how to find the equivalent resistance in this particular problem. What's messing me up is the 2k[tex]\Omega[/tex] and 10k[tex]\Omega[/tex] resistors...and the gap that is between them. I've just never done a circuit like this I guess.

My attempt to find the equivalent is below:

*In Series, Left Side:*300 and 300 ohm = 600 ohm

*In Series, Right Side:*200 and 1000 ohm = 1200 ohm

Simplified Resistor: 600 ohm on Left, 1200 ohm on right, 2k and 10k ohm on top.

The equivalent can be found by adding up in series: 600, 1200, 2000, and 10000 = 13,800ohms = 13.8kOhm. Is that correct? If not, how do I attack the equivalence problem?