Solve Simple Circuit Question: Equivalent Resistance Calculation

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Discussion Overview

The discussion revolves around calculating the equivalent resistance of a simple circuit, as presented in a homework problem. Participants are exploring the relationships between resistors in the circuit, particularly how to treat R2 in relation to R1 and R3. The scope includes theoretical understanding and application of circuit analysis principles.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • The original poster seeks clarification on whether R2 can be considered in parallel with R1 and R3.
  • Some participants suggest that the image of the circuit needs approval before further assistance can be provided.
  • One participant offers a hint regarding the behavior of current in circuits, stating that it travels the path of least resistance.
  • Another participant points out a potential error in the circuit reduction, suggesting that the current source may create a short circuit, which could affect the analysis.

Areas of Agreement / Disagreement

There is no consensus on how to approach the problem, as participants have raised different points regarding the circuit's configuration and the treatment of the resistors.

Contextual Notes

The discussion highlights potential limitations in the original circuit representation, including the need for clarity on the configuration and the implications of the current source on the circuit analysis.

jmcmillian
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Homework Statement


Find the equivalent resistance for this simple circuit.
(Image Attached)

Homework Equations


Equivalence Equations
In parallel: (1/R1 + 1/R2 + ... +1/Rn)^-1
In parallel (2 Resistors): (R1*R2)/(R1+R2)
In Series: R1+R2+...+Rn

The Attempt at a Solution


This was a much more complex circuit but I have it down to this.

My question...How do you treat R2 with Respect to R3 and R1? Could they be seen as all in parallel?
 

Attachments

  • circuit2.jpg
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Once your posted image is approved I will try to help.
 
Hint: Current travels the path of least resistance
 
You should post the original circuit. What you have now is just a short circuit across the current source. You may have made a mistake in the reduction.
 

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