Recent content by jmgXD6

So where would the bottom angle of elevation go then?

So where I had 25 degrees it should be 28.5, and 65 should be 61.5 degrees, correct?

I know where to put the lower triangle, but where would the top angle of evaluation, 28.5 degrees, go? Here's what I drew so far. http://s288.photobucket.com/user/ACE6911/media/PreCalculus%20questions/precalculusquestion85_zpse8fde88e.jpg.html?sort=3&o=0

Where did you get 3.5° and where would the 28.5° angle go?

Homework Statement An Antenna that is 90 feet high is on top of a hill. From a point at the base of the hill, the angles of elevation to the top and bottom of the antenna are 28.5° and 25°, respectively. To the nearest whole number of feet, how high is the hill? A, 189 ft B, 213 ft C...

It was in my physics book, the square root of k over m times the square root of A squared minus x squared. Is the amplitude of motion the same as x, .1 or is it .01? I just forgot to put it into parentheses.

I found v=+ or -√(k/m)√A^2 -x^2 with A equals the amplitude of motion but what's the amplitude of motion?

But how would you get velocity?

1. When a 0.20-kg block is suspended from a vertically hanging spring, it stretches the spring from its original length of 0.050m to 0.060m. The same block is attached to the same spring and placed on a horizontal, friction-less surface. The block is then pulled so that the spring stretches to...

I feel dumb now, our teacher likes to round and one of the answer choices is 98. Thanks guys.

So then if that's the case then 1.95 kgm/s=Ft and t equals .020 I would get 97.5 for force but that isn't an answer choice. What am I doing wrong?

It goes from .975 kgm/s to -.975 kgm/s so it changes by 1.95 kgm/s.

Alright, thank you very much for your help.

A .065-kg tennis ball moving to the right with a speed of 15 m/s is stuck by a tennis racket, causing it to move to the left with a speed of 15 m/s. If the ball remains in contact with the racket for 0.020s, what is the magnitude of the average force experienced by the ball? F=mv/t I think...

Alright so I multiply 5.5 by 2*pi and I got 34.557 then I multiply that by 0.6 and got 20.7, which is close to 21 rad. However it asked for angular displacement of the baseball as it's travels from the pitcher to the catcher. So how would I use Magnus effect to find the angular displacement?