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**1. When a 0.20-kg block is suspended from a vertically hanging spring, it stretches the spring from its original length of 0.050m to 0.060m. The same block is attached to the same spring and placed on a horizontal, friction-less surface. The block is then pulled so that the spring stretches to a total length of 0.10m. The block is released at time t=0 s and undergoes simple harmonic motion.**

0.20 kg

[_]-/\/\/\/\|

________spring

1. What is the maximum acceleration of the block?

2. What is the frequency of the motion?

3.What is the total mechanical energy of the system at any instant?

**F=mg=-k/x**

a=(-k/m)x

ω=2∏/T

Emechanical energy=U+k

a=(-k/m)x

ω=2∏/T

Emechanical energy=U+k

**For acceleration it should be 98m/s because when the mass was hanging down the spring x=.010m and F=1.96 that would mean -k=196 then plugged into a=-k/m*x with .1 as x the answer should be 98m/s. I'm sure it's right, but let me know if I'm wrong. I'm having trouble though finding the other two answers, for frequency of motion I can't find time and for mechanical energy I can't find the equation for potential energy in a spring.**

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