Recent content by JohanM

Homework Statement Assume that the pin joints at A,E, and F, are attached to the rest of the truck body, which is not shown. If a 8-kN weight is concentrated on the fork as shown, find the forces that the pins on member CDE experience. All joints can be modeled as pins. The Attempt at a...

Homework Statement In order to manually drill a hole, as shown below, it is important to keep the drill perpendicular to the surface. The drill is spun by a 30-lbf force applied downward at the handle at B, while pressure on the bit at A is obtained by applying a 10-lbf force along the x-axis...

Homework Statement Consider the rigid beam below, which is loaded by five forces shown. The forces at A and B act to keep the total force on the bar equal to zero and the sum of the moments about point A equal to zero. a) Find the forces at A and B that satisfy the conditions stated above...

Homework Statement A point charge Q is on the axis of a short cylinder at its center. The diameter of the cylinder is equal to its length L (see figure). What is the total flux through the curved sides of the cylinder? [Hint First calculate the flux through the ends. Homework Equations...

I did try using L'Hospital's rule, only to get limx->0 (ex-1)/(sin(x)+x*cos(x)) Trying to use L'Hospital's repeatedly only makes the denominator more and more complicated. Are you suggesting using L'Hospital's rule after replacing ex and sin(x) with their Maclaurin series? EDIT...

Homework Statement Find limx-> 0 [(ex-1-x)/(x*sin(x))] The Attempt at a Solution I tried using the Maclaurin series of ex and sin(x) to get [1+x+x2/2!+x3/3!+ ... -1 -x]/[x2-x4/3!+x6/5!-...] but I don't know how to achieve the final answer of 1/2

edgepflow: Thanks! It's so much clearer now, I appreciate your quick response. PA-PB=(1/2)ρ(vB2-vA2) PA-PB=ρg(h1-h2) (1/2)ρ(vB2-vA2) = ρg(h1-h2) (h1-h2)=Δh=(vB2-vA2)/(2g) Δh=3.0 m EDIT: I'm assuming my answers to (a) and (b) are correct since you didn't comment on them. Is that right?

edgepflow: Could you explain how Pb-Pa=ρg(h1 - h2)? Solving for Pb-Pa in Bernoulli's equation, I get Pb-Pa=(1/2)ρ(va^2-vb^2) I'm not sure how this ties to the height of the water in the columns. To me it seems to only relate the velocities, pressures, and heights of the two ends, A and B.

Homework Statement Consider a water pipe that tapers down from a diameter dA= 5.0 cm at end A to a diameter dB = 2.5 cm at end B. At each end a vertical pipe that is open to the air at the top is attached to the pipe as shown in the Figure. (Not to scale, the pipes are much taller than shown.)...