Hi guys -
Here's the problem I'm stuck on:
In a physics laboratory experiment, a coil with 160 turns enclosing an area of
13.7 (cm^2) is rotated during the time interval 4.60×10−2(s) from a position in which its plane is perpendicular to Earth's magnetic field to one in which its plane...
Doc -
Sorry it took a bit to follow up. I think I understand what you are saying - By using superposition, we are effectively able to substitute a -charge density for the small cylinder. Because the charge density, \rho, is 0 for the small cylinder, we can establish -\rho to allow it to...
Thanks -
By that, do you mean that I should replace the hole with point charges that equal out to a 0 net charge? Sorry, I'm not sure if I'm following you exactly
Thanks again
Jordan
Hi all - I reposted this here, as I posted in the advanced forum on accident:
Here's the problem I am having trouble with:
A very long, solid insulating cylinder with radius "R" has a cylindrical hole with radius "a" bored along its entire length. The axis of the hole is a distance "b"...
Doc -
Thanks for your insight - I'm glad someone else thinks this is a difficult problem, as I was beginning to feel like i just wasn't catching on. I am going to take another look at this problem this afternoon when I finish some other work, and I will post my progress. One question -...
Hi all -
Here's the problem I am having trouble with -
Basic Atwood machine setup -
Two masses are hanging from a pulley
m pulley = 2.0kg
frictional torque from pulley = .50 Nm
radius of pulley = .06m
mass1 = 4.0kg
mass2 = 2.0kg
The system is at rest with mass1...
Hi guys -
Here's the problem I am chewing on:
A binary star system consists of two stars, each equal to the sun in mass. The distance between the two stars is 1.0 X 10^12m. A comet which is essentially at rest, begins to make its journey toward the binary star system as a result of...
Beautiful -
That's exactly what i was missing - It totally makes sense as the PE is increasing as the KE goes down toward the top of the coaster. That's what I didn't think to factor into the final equation.
I really appreciate your help, and you have saved me a couple extra hours of...
Thanks for your response!
So the radial acceleration in circular motion is (v^2/R), and when it is set equal to the acceleration of gravity, you can conclude that Vmin = sqrt (gR).
Now, I'm thinking that we need to know the velocity at the bottom of the ramp entering the loop, and we can...
Hi All -
Here's the problem I have:
A block of mass m slides down a frictionless track, then around the inside of a circular loop-the-loop of radius R. What minimum height h
must the block have to make a full run around the loop without falling off? The answer is to be given as a...