Homework Statement
find the length of y=3sin(x+x^2)
find its length and area
Homework Equations
length: integral of square root of 1+ (dy/dx)2 dx
area: integral 2pix square root of 1 + (dy/dx)^2 dx
The Attempt at a Solution
dy/dx = 3cos(x+x^2)(2x)
Homework Statement
integral of x^2ln(x)dx
Homework Equations
The Attempt at a Solution
u=ln(x)
du= 1/x
dv=x2dx
x^3/3
integral x^2ln(x)dx = ln(x)x^3/3-intergral(x^3/3)(1/x)
Homework Statement
lim
x-o+ (tan(4x))^x
Homework Equations
The Attempt at a Solution
to get the derivative i have to use the chain rule so it would be.
lim
x- 0+ (x(tan(4x)^x-1)(sec^2(4)
That way, the integral is
\int_{\pi/4}^{\p/3} \frac{cos(\theta)d\theta}{cos(\theta)}= \int d\theta
which is very easy!
so does that mean the integral of (pi/3)-(pi/4)
just the upper limit minus the lower limit
that is correct, so what i have to do is use trig substitution. ill give it a try.
lets see:
u= arcsin
du= 1/(sqrt(1-t^2)) dt
i could then take the 2 outside the integral sign and get 2(integral of arcsin)
lets see:
from the original equation:
u= t^3
du= 3t^2
(1/3)du=t^2
ok so i messed up. i accidently substituted u in for t^2 but u=t^3.
first i have to make sure my substitution values above are right and if using substitution is the right method for solving the problem. is it?