Recent content by jpd5184

  1. J

    Calculating Length and Area of y=3sin(x+x^2)

    what do you mean it can be integrated. why not. its a question i was asked in class so i would think it can be solved.
  2. J

    Calculating Length and Area of y=3sin(x+x^2)

    so its the integral of the square root of 1+ (3cos(x+x^2)(2x+1))^2 integral of cos(x) is sin(x) would i use u substitution. then it would be 1+ u^3/3
  3. J

    Calculating Length and Area of y=3sin(x+x^2)

    dy/dx = 3cos(x+x^2)(2x+1) im not so sure how to to the integral though.
  4. J

    Calculating Length and Area of y=3sin(x+x^2)

    yes around the y-axis. i need help integrating dy/dx do i use u substitution or can i just integrate right away
  5. J

    Calculating Length and Area of y=3sin(x+x^2)

    sorry about that: 0 < x < pi/2 both are greater than or equal to and less than or equal to.
  6. J

    Calculating Length and Area of y=3sin(x+x^2)

    Homework Statement find the length of y=3sin(x+x^2) find its length and area Homework Equations length: integral of square root of 1+ (dy/dx)2 dx area: integral 2pix square root of 1 + (dy/dx)^2 dx The Attempt at a Solution dy/dx = 3cos(x+x^2)(2x)
  7. J

    How can integration by parts be used to solve this integral?

    Homework Statement integral of x^2ln(x)dx Homework Equations The Attempt at a Solution u=ln(x) du= 1/x dv=x2dx x^3/3 integral x^2ln(x)dx = ln(x)x^3/3-intergral(x^3/3)(1/x)
  8. J

    Using the Chain Rule to Find the Derivative of a Complex Function: Homework Help

    thanks very much, i did learn this technique, just forgot it.
  9. J

    Using the Chain Rule to Find the Derivative of a Complex Function: Homework Help

    Homework Statement lim x-o+ (tan(4x))^x Homework Equations The Attempt at a Solution to get the derivative i have to use the chain rule so it would be. lim x- 0+ (x(tan(4x)^x-1)(sec^2(4)
  10. J

    How to Calculate the Integral of 2/(sqrt(1-t^2)) dt?

    pi/12 isn't giving me the right answer
  11. J

    How to Calculate the Integral of 2/(sqrt(1-t^2)) dt?

    so it would be pi/3 - pi/4 this would be 4pi/12 - 3pi/12 which would be pi/12 for the answer since its a integral would it be pi/12 + c
  12. J

    How to Calculate the Integral of 2/(sqrt(1-t^2)) dt?

    That way, the integral is \int_{\pi/4}^{\p/3} \frac{cos(\theta)d\theta}{cos(\theta)}= \int d\theta which is very easy! so does that mean the integral of (pi/3)-(pi/4) just the upper limit minus the lower limit
  13. J

    How to Calculate the Integral of 2/(sqrt(1-t^2)) dt?

    that is correct, so what i have to do is use trig substitution. ill give it a try. lets see: u= arcsin du= 1/(sqrt(1-t^2)) dt i could then take the 2 outside the integral sign and get 2(integral of arcsin)
  14. J

    How to Calculate the Integral of 2/(sqrt(1-t^2)) dt?

    lets see: from the original equation: u= t^3 du= 3t^2 (1/3)du=t^2 ok so i messed up. i accidently substituted u in for t^2 but u=t^3. first i have to make sure my substitution values above are right and if using substitution is the right method for solving the problem. is it?
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