Recent content by justaus3r

I supposed that the change in height = height_big - height_small

Area = 20 m^(2) Before melting I think i solved it but correct me if i am wrong if the height increased due to floatation of that ice layer with the body equals 2 * 10 ^(-3) m since the body is floating therefore the M_body*g = ρ_water * vol._immersed * g vol_immersed = M_body / ρ_water =...

their masses are equal but their volumes aren't equal, right ?

it displaces amount of water equals to the upthrust force acting on ice from surface of water I think it remains the same (am not sure though )

Ok, as for the ice part should i include it or i can't bec. i don't have its area ?

thanks in advance for helping but unfortunatly i don't have the height of water in the pool

archimedes' principle includes cases where opposing force(s) has higher value than upthrust force which leads to the sinking of the body

yes R.D. is relative density = Density of material / density of water it increases

Homework Statement A swimming pool with 5 M length and 4 M width.A big layer of ice floats on the surface of the pool and above the layer of ice a rock with 40 KG mass and 5 R.D.,If the ice is melted and the rock fall, calculate the change in the height of water in the pool final answer...