Recent content by kashmirekat

The answer to the problem involved taking the ratio of masses to the ratio of r. m/[delta]m=[delta]r/r . Where [delta]r = .5mm Thank you for your help.

Nevermind, Telsa is in kg so for it to cancel I have to use kg. Thanks.

Okay, I understand that their is going to be a circular path due to the magnetic force (E field) and that since the masses of the molecules are nearly the same, their velocity is going to be the same too. However, I do not understand where the .5mm is integrated into the equation. I'm...

I was afraid that would not be enough info, the entire question is as follows: Suppose the e field between the e plates in the mass spec is 2.48x10^4 v/m and the magnetic fields B=B'=0.68T. The source contains carbon isotopes of mass #s 12, 13, 14 from a dead tree. (estimate masses by x by...

Here's a verbatim section of the problem: " The source contains carbon isotopes of mass numbers 12, 13, 14 from a long-dead piece of a tree. (To estimate atomic masses, multiply by 1.67x10^-27kg). " My question is isn't the 12, 13, & 14 in the atomic mass units already (Carbon-12 has an amu...

I have two molecules CO and N2 with masses 28.0106u and 28.0134u respectively. I need to determine the radius of curvature the spectrometer must have if the molecules are to be separated on film by 0.50mm. I don't even know where to begin to solve this. The only equation relating to it in...

Ohhh, yeah. I knew that. :) Geez I am good at confusing myself. Thank you for your help.

Would the equation be I3 + I5 = I (no subscript) or I3 + I5 = I1?

Verify Equations Please see attached image for circuit. I have labeled all my current directions. For each Rn, that is the corresponding In. (ie. I1 goes w/R1) I would like for you to verify my equations below for solving this circuit using Kirchhoff's Rules of voltage and current...

Circuit Current I have the circuit below (also attached as an image): Note: ^^^^ & <<<< = resistors [-]=power supply ...=just space (-) & (+) indicates + & - side of battery A,B represent the junctions |-----^^^^------A-----^^^^------| |......|......| <......<......(-)...

I was in the middle of asking a question about the signs and your response answered it perfectly. Thank you.

I start with this equation: (8 / (L^2 + 2xL + x^2)) = -(-2/x^2), cross multiply 8x^2 = -2(L^2 + 2xL + x^2), divide by -2 -4x^2 = L^2 + 2xL + x^2, add -4x^2 0 = L^2 + 2xL + 5x^2, not L^2 + 2xL - 3x^2 as I had originally hoped for. So, how do you solve for x (in terms of L) for this...

I'm using 8 for q1 and -2 for q2.

Hello all, I have two charges, q1 & q2, along a horizontal axis of length L. I supposed to determine the length at which another charge, Q, can be placed so that its net force is zero, other than infinitely away. I'm using the equation: F = kq1Q / r + kq2Q / r -- > kq1Q / (L+x)^2 = -(...

A 5/8 inch diameter (inside) garden hose is used to fill a round swimming pool 7.2m in diameter. How long will it take to fill the pool to a depth of 1.5m if water issues from the hose at a speed of 0.28m/s? 5/8in = 0.0159m A = pi(3.6m)^2 = 40.7 m^2 V = (40.7m^2)(1.5m) = 61.07 m^3 v =...