Recent content by KatieD

EPE= Vq so if the force goes up... and the mass is the same the acceleration will have to go up with the second one by 2 right?

so here's where i am at: r1=mv/qB r2=mv/2qB I then divide r1 and r2 getting ((m1v1)/(qB))/((m2v2)/(2qB)) then with canceling out I get r1/r2=2 I am confused, the teachers notes say its the square root of 2, I am not sure where this comes in

Homework Statement The ion source is a spectrometer produces both singly and doubly ionized species, X+ and X2+. The difference in mass between these species is too small to be detected. Both species are accelerated through the same electric potential difference, and both experience the...

(sorry it took me so long I had to leave for physical therapy)

Oh an equipotential surface! so the electric field would be perpendicular to the surface!

You won't measure any voltage, does this mean that the electrical field would be zero?

Homework Statement If electric fields are perpendicular to the equipotential surface, what is the orientation of the field on the surface of a conductor (like metal)? Why is this so? Homework Equations E= ∆V/d The Attempt at a Solution I know that there is no charge within a...

Ok, I can't seem to get the right answer and I don't know where I'm going wrong. I set the equation up as F = k(q1 + ex)(q2 - ex) / r^2 where q1 is the positive charge and q2 is the negative charge. So this works out to 68 = (8.99*10^9)(2*10^-6 + x*1.6*10^-19)(-2*10^-6 - x*1.6*10^-19) /...

okay got ya, I just need to take it into consideration with the initial formula instead of solving for just q I am solving for q+ex

q/e is going to be the number of e. But I guess that would be the number of e- for that charge. So they ask for the e- to change the charge. Would I then find the difference by subtracting from 2 and then dividing by e-?

F = K*Q^2/r^2 68 = (8.99 * 10^9 N * m^2/C^2)(q^2)/(3*10^-2)^2 q=2.6*10^-6 C e=1.6*10^-19 (2.6*10^-6C)/(1.6*10^-19)=1.63*10^13 the answer in the back is 3.8*10^12

Coulombs Law Problem -- Find the Force Homework Statement Two small objects, A and B, are fixed in place and separated by 3 cm in vacuum. Object A has a charge of 2 uC and object B has a change of -2 uC. How many electrons must be removed from A and put onto B to make the electrostatic force...