Coulombs Law Problem - Find the Force

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Homework Help Overview

The discussion revolves around a problem involving Coulomb's Law, specifically calculating the electrostatic force between two charged objects, A and B, and determining the number of electrons that need to be transferred to achieve a specific attractive force.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between charge and the number of electrons, with some attempting to derive the necessary charge to achieve the desired force. Questions arise regarding the setup of equations and the interpretation of variables.

Discussion Status

Several participants are actively engaging with the problem, sharing their calculations and questioning the setup of their equations. There is a mix of attempts to clarify the relationship between charge and the number of electrons, as well as discussions about potential errors in calculations.

Contextual Notes

Participants note the challenge of transitioning from simpler Coulomb's Law problems to this more complex scenario, highlighting the need to consider initial conditions and the effects of transferring charge.

KatieD
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Coulombs Law Problem -- Find the Force

Homework Statement


Two small objects, A and B, are fixed in place and separated by 3 cm in vacuum. Object A has a charge of 2 uC and object B has a change of -2 uC. How many electrons must be removed from A and put onto B to make the electrostatic force that acts on each object an attractive force whose magnitude is 68 N?

We know an electrons charge is 1.60*10^-19 C

Homework Equations


F=kq1q2/r^2 (coulombs law)

The Attempt at a Solution



I tried to solve for q (the charge). Since they are both the same I took the square root. Then I divided by the charge of e-. I am out of ideas :(

I can do simple coulombs law problems in this chapter, but the harder ones like this stump me. :((Thanks,
Katie
 
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KatieD said:
I tried to solve for q (the charge). Since they are both the same I took the square root Then I divided by the charge of e-.

So after doing this, what is the quantity that you have arrived at? What is q/e?
 


F = K*Q^2/r^2
68 = (8.99 * 10^9 N * m^2/C^2)(q^2)/(3*10^-2)^2
q=2.6*10^-6 C
e=1.6*10^-19
(2.6*10^-6C)/(1.6*10^-19)=1.63*10^13

the answer in the back is 3.8*10^12
 


I'm not asking for the number.

I'm saying: if q is the charge, and e is the charge per electron, what does the quantity q/e mean? How does that relate back to what the question wants?
 


q/e is going to be the number of e. But I guess that would be the number of e- for that charge. So they ask for the e- to change the charge. Would I then find the difference by subtracting from 2 and then dividing by e-?
 


The question wants x electrons per object.
You just calculated the no. of electrons you need
From the question you can find out how many electrons you had at the start.

Hopefully its obvious enough now?
 


okay got ya, I just need to take it into consideration with the initial formula
instead of solving for just q I am solving for q+ex
 


Ok, I can't seem to get the right answer and I don't know where I'm going wrong.

I set the equation up as

F = k(q1 + ex)(q2 - ex) / r^2

where q1 is the positive charge and q2 is the negative charge.

So this works out to

68 = (8.99*10^9)(2*10^-6 + x*1.6*10^-19)(-2*10^-6 - x*1.6*10^-19) / (3*10^-2)^2

but this doesn't lead to the right answer. Where is my set up going wrong?
 


It does, I've checked. Calculator error somewhere?
 

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