Recent content by Kerrie yu

..wait ..so since I am starting another one,, everything before 5sec doesn't matter,, so my vi is not 20m/s anymore?

Wait no,,, di =100 , df is unknown

So we r starting new after 5sec? Df=100 ,vi=20, tf=0 ,a= -6 substitute these numbers?

The second one? Df=...

So for the displacement vs time graph, the line would be going up from 0 to 100 ( take 5 sec) and then from 6 sec, it starts going down by 6 because of the acceleration. 5s=100m, 6s=94m and so on?

But first I need to know if constant speed is equal to velocity. So if there is a constant speed of 20m/s , is it mean that the velocity is constant 20m/s ?

The speed is a constant of 20m/s for 100m (moving on a straight line) after 100m, the car stops at a constant 6m/s/s. *So in this case, speed is equal to velocity? *How do you graph velocity vs time graph and acceleration vs time graph?

Oh yea,, its something like the acceleration cannot be 0 because if it is , it againsts the gravity ...something like that..right?

Oh wait,,, nvmm thxx

But wouldn't there be a difference since the downward direction is positive

What would the velocity and acceleration be if a person was tossing a ball upward but downward direction is positive? When the ball was falling down, what would the velocity and acceleration be?