Recent content by kevinr
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Deriving the Electric Field from the Electric Potential: A Calculus Approach
ah ok ;) makes sense. Thanks!- kevinr
- Post #3
- Forum: Introductory Physics Homework Help
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Deriving the Electric Field from the Electric Potential: A Calculus Approach
Homework Statement The potential as a function of position in a region is given by V(x) = 3x - 2x^2 - x^3. (x in meters and V in volts). Find equation for electric potential field. Homework Equations v = integral(E * dr) The Attempt at a Solution I tried taking the derivative of...- kevinr
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- Electric Electric potential Field Potential
- Replies: 2
- Forum: Introductory Physics Homework Help
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Solving Simple Harmonics: Return Time After Collision
Ah ok thank you i got it now!- kevinr
- Post #5
- Forum: Introductory Physics Homework Help
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Solving Simple Harmonics: Return Time After Collision
"There are a few (fun!) ways to solve this problem." :D I can't any find of the fun ways to do this problem. I know f and T but what do i do with that? (im thinking that it since my T = 3.24, it should be less) right?- kevinr
- Post #3
- Forum: Introductory Physics Homework Help
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Solving Simple Harmonics: Return Time After Collision
[SOLVED] Simple Harmonics Homework Statement A 10.0 kg mass is traveling to the right with a speed of 2.40 m/s on a smooth horizontal surface when it collides with and sticks to a second 10.0 kg mass that is initially at rest but is attached to a light spring with force constant 75.0 N/m...- kevinr
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- Harmonics
- Replies: 4
- Forum: Introductory Physics Homework Help
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Simple Harmonics - Kind of wierd
O ok it works in radians. Thanks!- kevinr
- Post #5
- Forum: Introductory Physics Homework Help
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Simple Harmonics - Kind of wierd
Its an equation given to me. Problem said exactly what i posted. Everything was given to me and everything is correct. When i solve this: i get .073965879 Can anyone confirm this? I tried that and it was wrong. (my calculator is in degrees mode - i think that's right)- kevinr
- Post #3
- Forum: Introductory Physics Homework Help
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Simple Harmonics - Kind of wierd
[SOLVED] Simple Harmonics - Kind of weird Homework Statement Question: A 1.30 kg mass on a spring has displacement as a function of time given by the equation: x\left( t \right) = \left( {7.40\;{\rm{ cm}}} \right)\,\cos\:\left[ {\left( {4.16\;{\rm{ s}}^{ - 1} } \right)t - 2.42}...- kevinr
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- Harmonics
- Replies: 4
- Forum: Introductory Physics Homework Help
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What Happens to Amplitude When One of Two Glued Balls on a Spring Detaches?
Thanks! I managed to figure it out after you Hint =D.- kevinr
- Post #8
- Forum: Introductory Physics Homework Help
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What Happens to Amplitude When One of Two Glued Balls on a Spring Detaches?
removed cause i figured out after the hint!- kevinr
- Post #7
- Forum: Introductory Physics Homework Help
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What Happens to Amplitude When One of Two Glued Balls on a Spring Detaches?
Ok so that means that the 17 cm i got is compared to the old equilibrium? If so, i have no idea how to get the new equilibrium point. Wouldnt the new equilibrium point be the new altitude you get? (since altitude is measured from equilibrium). Thanks for help!- kevinr
- Post #5
- Forum: Introductory Physics Homework Help
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What Happens to Amplitude When One of Two Glued Balls on a Spring Detaches?
Amplitude after the small ball has fallen off. (of the big mass only) Oops forgot that- kevinr
- Post #3
- Forum: Introductory Physics Homework Help
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What Happens to Amplitude When One of Two Glued Balls on a Spring Detaches?
[SOLVED] Simple Harmonics Question Homework Statement A 1.40 kg ball and a 2.20 kg ball are glued together with the lighter one below the heavier one. The upper ball is attached to a vertical ideal spring of force constant 170 N/m, and the system is vibrating vertically with amplitude 19.0...- kevinr
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- Harmonics
- Replies: 7
- Forum: Introductory Physics Homework Help
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How Do You Calculate Maximum Theta Between Two Buildings in Related Rates?
[SOLVED] Related Rates - Sort of confused Homework Statement There are two buildings. One 20' high and other 40' high with a 60' distance between them. A person walking between them creates a theta with the buildings (see pic) PICTURE...- kevinr
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- Confused Sort
- Replies: 2
- Forum: Calculus and Beyond Homework Help