Deriving the Electric Field from the Electric Potential: A Calculus Approach

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SUMMARY

The electric potential function is defined as V(x) = 3x - 2x² - x³. To derive the electric field E from this potential, the correct approach involves taking the negative derivative of V with respect to x, expressed as E = -dV/dx. The calculation yields E = - (3 - 4x - 3x²), which simplifies to E = -3 + 4x + 3x². The critical aspect to remember is the inclusion of the negative sign when deriving the electric field from the potential.

PREREQUISITES
  • Understanding of calculus, specifically differentiation
  • Familiarity with electric potential and electric field concepts
  • Knowledge of vector calculus, particularly gradient operations
  • Basic physics principles related to electromagnetism
NEXT STEPS
  • Study the relationship between electric potential and electric field in electrostatics
  • Learn about gradient operations in vector calculus
  • Explore applications of electric fields in real-world scenarios
  • Investigate the implications of negative signs in calculus derivatives
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Students in physics or engineering, particularly those studying electromagnetism, as well as educators looking for clear examples of deriving electric fields from potentials.

kevinr
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Homework Statement



The potential as a function of position in a region is given by V(x) = 3x - 2x^2 - x^3. (x in meters and V in volts). Find equation for electric potential field.

Homework Equations



v = integral(E * dr)

The Attempt at a Solution



I tried taking the derivative of v to get E but it keeps says I am missing something. So first i tried, 3-4x-3x^2 but its off by a multiple and than i figured since v is the integral of E * displacement --> meaning the derivative of V is E so i got what i got before and decided to divide by X which got me 3/x - 4 - 3x which also didnt work.

Im not sure quite what to do.
 
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The electric field is given by

[tex]E = - \vec{\nabla}V[/tex]

In this case,

[tex]E = -\frac{dV}{dx}[/tex]

Your forgetting the minus sign.
 
ah ok ;) makes sense.

Thanks!
 

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