Recent content by kieran1black2

but that has nothing to do with the stochastic model or probability model... i need a formula or set of steps not a tool...

I have an exponential function graph that was given to me as a question i had to find the points and find three different ways of finding the area under the curve. I found an Empirical model (finding the formula and integrating from one point to another) I found a Finite Element model...

I was given a very open ended question stating... "How Long will it take to break into a line of traffic at a 'T' intersection" I need some sort of start like a theory that includes this kind of thing. We have been studying probability this term so i need something to do with a...

yer you get (1/30)[(1/-142000)/(142000+30v)] now what?

im only in grade 12... i don't have the time to take a day off or read calulus texts... i just need some one to tel me what to do and how to integrate it

if this is true: 1/30((142000+30v)/(142000+30v)-142000/(142000+30v)) how do i then integrate it?

nah I am only in grade 12 in australia... i just need som help integrating this so i can solve a "flight" plan of a particle with variable acceleration... if you can help me with this it would be great

if you think you can do it without that transition... go for it... that's just how i interpreted the question

1/30((142000+30v)/(142000+30v)-142000/(142000+30v)) like this? what does this achieve?

Homework Statement the trouble is in the integration on the left side (go straight o my answer down the bottom of the page)... please help me... mg-u-kv=m*a where (all constant) m= mass= 3000 g=gravity=10 u=thrust=172000 k=30 v=velocity=variable a=acceleration=variable...

Homework Statement the trouble is in the integration on the left side (go straight o my answer down the bottom of the page)... please help me... mg-u-kv=m*a where (all constant) m= mass= 3000 g=gravity=10 u=thrust=172000 k=30 v=velocity=variable a=acceleration=variable...

what i ended up with is (e^-t/100)/(-30/100) x e^(-1205.525/-100)/t - 142000/30t that is after integration... is that what you meant?

i have already tried that... it didnt seem to work... could you show it in latex? so i can see what I am doing wrong?

please help me with the integration in the word document.

for question 4.) mg-kv^2-u=m*v(dv/ds) i got (using the constant values 1/0.06*ln(|142000+0.03v^2|)=-1/3000*S+c when S=0, v=1000 therefore c=200.921 -1/3000*S=1/0.06*ln(|142000+0.03v^2|)-200.921 when v=0, S=? therefore S=9583.88 m using this same method i need the others...