Recent content by KingDaniel

Hi, I read that an ideal fluid needs to be frictionless and incompressible. Please explain why, especially the incompressible part? Thanks

@analogdesign , Oh yeah, of course. My bad. Thanks

Hi, I came across a question from our weekly set of questions that involved finding the inductive reactance and capacitive reactance, ie: XL = jwL and XC = 1 / jwC. In the solution sheet, the professor wrote that the frequency, w (omega) = 10000, however, in the question sheet, it was nowhere...

@Chestermiller , okay. Thanks

@Chestermiller , okay, but isn't that already included, as h = u + pv ?

Yes, my question, as stated already, is My attempt to the solution along with the picture of what I'm talking about is attached too...as well as the steady-flow energy equation that I need to be simplified for this particular situation. Is my simplification correct? If not, please advise further

Homework Statement I'm not too sure about my attempt to this question, but what is the simplified Steady Flow Energy Equation for a water pump that has one inlet at the bottom and one outlet at the top, and a work input? Homework Equations Q^ = W^ + m^[(h2 - h1) + 1/2 (c22 - c12) + g(z1 - z2)]...

Thanks @axmls , still seems like a pretty long and laborious task. But basically, the magnitude of the transfer function enables us to get the amplitude of yss(t) and the angle of the transfer function is the phase difference between the input and the output?

Homework Statement Finding the complete response (steady-state and transient) is a long and laborious task. My lecturer's notes read (since at our stage of the course, we're mostly interested in the steady-state part of the solution and not so much the transient) : "The simple method for...

Finding the complete response (steady-state and transient) is a long and laborious task. My lecturer's notes read (since at our stage of the course, we're mostly interested in the steady-state part of the solution and not so much the transient) : "The simple method for finding the steady-state...

@Hesch , okay, so after finding G(jω), knowing the amplitude and phase will help us get the steady-state part of the response? Also, I still don't get why, in G(s), we substituted "s" with just "jω" only while "s" actually equals "a+jω" and not just "jω".

Homework Statement Hi, When finding the steady-state response to a sinusoidal input, since "s" is a complex number, (a + jw), why do we substitute "s" with only the imaginary part (jw) in the transfer function, G(s) , to get G(jw), rather than substituting the whole complex number to get G(a +...

Homework Statement Hi, How come, for a refrigerator and a heat pump, we don't consider the changes in energy for the refrigerant for when the pressure drops (at expansion valve) and when it rises (at the compression valve)? We only consider the changes in energy when it evaporates and...

@Student100 , also, what makes it wrong?

@DEvens , I never said anything about it not working. I said a heat pump and a refrigerator do the exact same thing. In both my examples, heat is being transferred from inside the fridge to outside, making it cooler and maintain the "cold". Therefore, the pot of hot soup would be cooled...