Substituting gives these two equations:
3I1+2I3=1
I1+2I3=1
The problem is when I try to subtract these equations I get:
2I1=0
How can the current be zero?
I have attached a picture of a circuit. I am trying to find the values of I1, I2, and I3.
What I have come up with so far, using Kirchhoff's Voltage and Junction Laws is:
I2=I1+I3
for the left loop:
9V - (5 ohms)I1 -4V - (10 ohms)I2 = 0
which simplifies to:
1V - (1 ohm)I1 - (2...
I have attached a picture of a circuit. I am trying to find the values of I1, I2, and I3. What I have come up with so far, using Kirchhoff's Voltage and Junction Laws is:
I2=I1+I3
for the left loop:
9V - (5 ohms)I1 -4V - (10 ohms)I2 = 0
which simplifies to:
1V - (1 ohm)I1 - (2 ohms)I2 =...
here are my forces:
where the beam meets the wall - friction (up) normal (right)
on the beam I have Wp and Wb pointing down and the normal force of the professor pointing up
on the far right, I have the tension which has a both an up (T_y) and a left (T_x) pointing component.
But I feel...
I've attached a picture of the problem I am referring to.
The pulley is placed so that the string makes a 45.0-degree angle with the beam. The beam is uniform, 5.00 meters long, and has weight w_{b}. The professor stands 2.00 meters from the pivot point and has weight w_{p}.
First, I am...
Yes, that makes perfect sense.
So, the wall can push or pull in whatever direction it is needed. But, who is to say which direction it is needed? Could I say that the wall exerts whatever force is needed to make the torque zero?
I really appreciate your help, I have a much better...
Do you literally mean any direction?
And, would this 'transformable' force concept be applicable to non-rotational dynamics problems? For example, when I am writing the net forces in the x and y directions, do I include the force ofthe wall? Or, is this force only associated with torque?
...and another...
The third part of this question asks me to find the y-component of force that the wall exerts on the beam (F), using the axis shown. I don't understand how the nomal force of the wall could have a y-component, since according to my free body diagram, it is simply a strictly...
Thank you, Doc Al.
Would it be appropriate to extend your advice a general "rule":
If a force passes through a particular point in a system, then it will not exert a torque on that point.
Also, could you tell me how to enter mathematical symbols when posting - I couldn't really glean...
This problem is regarding the attached jpeg.
I am supposed to find the tension in the cable. I know that since the setup is in equilibrium, all net forces and torques equal zero. So,
Since net F(x) = 0, Tcos@ = F
and net F(y) = 0, Tsin@ = g(m1+m2)
@=theta
F=the normal...