Recent content by klg.amit

I think you need to state your question more clearly edoctor. Usually when you say that you have information about an object in a certain frame it presupposes that this frame is fixed relative to the object so no more velocities and so on need to be added into get the "real" information.. If...

Let's continue this a bit just to prove that you can get m also by dividing the magnitudes ... Square each equation and sum it all up: Fx2 + Fy2 + Fz2 = m2(ax2+ax2+ax2) Another way of writing this is: |\vec{F}|^2 = m^2 |\vec{a}|^2 m is positive so from here you see that: m =...

And the conservation here of course is reflected by an increase in the kinetic energy which is equal to the decrease in the potential energy

I see, indeed these are good examples of the same thing. Thanks again!

I think I understand now, the hoop rotates through an angle \phi solely on the account of its movement on the cylinder (simply because of the geometry, on flat surfaces this contribution doesn't occur) and through \theta due to rolling without slipping, is that a good way to see it ? I think...

Hi, The following is a general question which doesn't have to do with any particular problem. (therefore I am not including the template). I understand that when a circular object (e.g: a hoop) rolls on a *flat* surface without slipping with angular speed \omega, its contact point, and thereby...

True. In that case I was just weak with making sense. Thank you :)

How do I integrate this part: β*g*cosα*s*ds I need to find an expression which when differentiated with respect to s gives s I thought it might be (β*g*cosα*s^2)/2 but then according to the chain rule when differentiating it should be multiplied by s' . I'm sorry but I'm really weak with DE ..

So the point of this method is to move from a second order (and non-separable?) DE to a separable DE ?

I got a clue from somewhere which seems to hint that I can do it another way The clue says to multiply both sides of the equation by \frac{ds}{dt} but I have no clue what this clue gives me :). That is, how to continue from there..

O.K. Thank you :) This clears up things a bit :smile: I need to look into that and harmonic motion more carefully.. (it is something which I actually haven't studied yet)

Homework Statement A small body starts sliding down an inclined plane. The angle between the plane and the horizon is \alpha. The coefficient of friction depends on the distance s that the body travels according to \mu = \beta s. Find the distance that the body travels until coming to a...