Recent content by Kp0684

Integrals of Rational Functions... The integral of:... (x-1)/x^4+6x^3+9x^2 , dx...i factored out the bottom getting: x^2(x+3)(x+3)...so, my new integral is: (x-1)/x^2(x+3)^2... now when i muiltlpy both sides by (x-1)/x^2(x+3)^2...i get... x-1= A(x+3)^2 + Bx^2(x+3) + C x^2...for A i got...

General Physics 1... A crate of mass 30.0kg rests on level surface. The coefficient of kinetic friction between the crate and surface is .400 . What force applied at an angle of 30.0 degrees below the horizontal (i.e. pushing down) is required to keep the mass moving at constant speed?......on...

iam thinking for part (b) i would use tan(11)= .1944 for the friction...am i doing this correctly...?

A circular curve of highway is designed for traffic moving at 60km/h. Assume the traffic consists of cars without negative lift. (a). If the radius of the curve is 150m, what is the correct angle of banking of the road? (b) If the curve were not banked, what would be the minimum coefficient of...

for a.) 196N b.) 118N c.) ...? for part a : Uk(Mg+sin20)= .25(80N*9.8m/s2 + sin20) = 196N , for part b: Us(Mg+cos20)= .15(80N*9.8m/s2+ cos20)= 118N...and for part c i don't know, i tryed using the the equation for part b, and i divided by 118N i got "0" i know its wrong...need help BIG...

A loaded penguin sled weighing 80N rests on a plane inclined at angle = 20 degrees to the horizontal. Between the sled and the plane, the coefficient of static friction is 0.25, and the coefficient of kinectic friction is 0.15. (a) What is the least magnitude of the force F, parallel to the...

i have the magnitude force equal to (6.82 x 10^3 N)...

A car traveling at 53km/h hits a bridge abutment. A passenger in the car moves forward a distance of 65cm (with respect to the road) while being brought to rest by an inflated air bag. What magnitude of force (assumed constant) acts on the passenger's upper torso, which has a mass of 41kg? ...

okay, i get -2.00i - 3.00j - 1.17k when i sum it up...iam still lost on this one...need help again...

What is the sum of the following four vectors in (a) unit- vector notation, and as (b) a magnitude and (c) an angle?... A=(2.00m)i + (3.00m)j...B: 4.00m, at +65.0 degrees...C= (-4.00m)i - (6.00m)j...D: 5.00m, at -235 degrees...i understand how to get the magnitude and the angle but how would i...

If B is added to C= 3.0i + 4.0j, the result is a vector in the positive direction of the y-axis, with a magnitude equal to that of C. What is the magnitude of B?... Solution, i got Rx= Ax+Bx+Cx , = (3.0i) and, Ry= Ay+By+Cy, = (4.0j) So, the square root of (3.0)2 + (4.0)2 = ... (5)...for the...

yeah i see what i did wrong i plugged in 2.5s...instead of 1.5 which it took the time to pass the tower...i thought it would be the where it reaches its max height for time...but i see how its done...thanks so much...

hey thanks so much for helping me out...for the answer i got h= 30.625m...iam not sure if that's the answer you would have got...but this is my setup... Vo= V + gt... i got 24.5m/s2...then i used Vo-1/2gt2...which i got it to be = 30.625m... Thank you for your help... Krishna Patel

A rock is thrown vertically upward from ground level at time t=0. At time t=1.5s it passes the top of a tall tower, and 1.0s later t reaches its maximum height. What is the height of the tower? ... is this the equation i would use... delta(Y)= Vo(t) + 1/2(a)(t2)...with Vo= 0 , t=1.5, a=...