Calc Coeff of Friction for 60km/h on 150m Curve

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To determine the angle of banking for a highway curve designed for 60 km/h on a 150 m radius, the calculation yields an angle of approximately 11 degrees using the formula tan-1(v²/(gR)). For the unbanked scenario, the minimum coefficient of friction required to prevent skidding at the same speed is being discussed. The user suggests using tan(11) to find the friction coefficient, which is approximately 0.1944. Clarification on the correct approach for calculating the friction coefficient is sought, indicating a need for further guidance on the equations involved.
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A circular curve of highway is designed for traffic moving at 60km/h. Assume the traffic consists of cars without negative lift. (a). If the radius of the curve is 150m, what is the correct angle of banking of the road? (b) If the curve were not banked, what would be the minimum coefficient of friction between tires and road that would keep traffic from skidding out of the turn when traveling at 60km/h?....for part (a). i used tan-1 (v2)/(gR)...i got v= 16.6m/s...g=9.8m/s2...R=150m...answer i got 11 degrees...what equation would i use for part (b)... :confused:
 
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iam thinking for part (b) i would use tan(11)= .1944 for the friction...am i doing this correctly...?
 

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