I've been looking at relative motion equations in 2d and having no problem but when I saw this one my brain was certain that somehow it had to be super complicated. Its not though. Thanks, is all makes sense now.
Homework Statement
A cheetah can run at approximately 100km/hr and a gazelle at 80km/hr. If both animals are running at full speed, with the gazelle 70m ahead, how long before the cheetah catches its prey?
Homework Equations
s=vt (no acceleration)
v = km/hr / 3.6 = m/s
The Attempt at a Solution...
I think I have it now.
2y = 1/2 at12 divided by y = 1/2 at22
gives me 2= t12t22
so t1t2 =square root of 1/2.
Thanks for your help, still not entirely sure I understand what I did. I guess that's what practice is for.
A ball moving with speed v rolls off a shelf of height h and strikes the floor below a distance x1 from the edge. A second ball moving with the same speed rolls of a self of height 2h and strikes the floor a distance x2 away from the edge. Determine the ratio of distances x1/x2.
\Deltax=Vxt...
Thank you
I tried the equation above and got an answer of Vi=0.23m/s
I am doing this course via distant education, so there is not much support. The print out they supplied did not even include the equation I needed to figure out this problem so I was searching online.
I really appreciate...
My, what a humbling comment. Right then, I'll go back to the equation I had originally used and I'll try to work it out.
3.0m=v_i + 1.2m/s/2 * 4.2s
3.0m/ 4.2s= 0.714
0.714-1.2=v_i/2
-0.486 x 2 = v_i
v_i = 0.97m/s
Should I just give up now?
So the equation is wrong? That's silly, I took it off of the website I was provided with through school. Go figure. So the answer is initial velocity is -0.843m/s. Is this right?
1. Can someone please help with this equation
2.An accelerating lab cart passes through two photo gate timers 3.0 m apart in 4.2 s. The velocity of the cart at the second timer is 1.2m. What is the cat's velocity at the first gate?
3. So I am so confused as to how to find the initial velocity. I...