Relative motion -cheetah and gazelle

AI Thread Summary
A cheetah running at 100 km/h and a gazelle at 80 km/h, with the gazelle starting 70 meters ahead, leads to a relative motion scenario. The cheetah closes the gap at a rate of 20 km/h, which translates to approximately 5.56 m/s. To determine how long it takes for the cheetah to catch the gazelle, the time can be calculated using the formula time = distance/speed, resulting in 12.6 seconds for the cheetah to reach the gazelle. The discussion emphasizes simplifying the problem by viewing it through the lens of relative motion. Ultimately, the solution hinges on understanding the relative speeds of both animals.
Kristin_Z
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Homework Statement


A cheetah can run at approximately 100km/hr and a gazelle at 80km/hr. If both animals are running at full speed, with the gazelle 70m ahead, how long before the cheetah catches its prey?

Homework Equations


s=vt (no acceleration)
v = km/hr / 3.6 = m/s

The Attempt at a Solution


I understand that this is relative motion. I've calculated that it takes the cheetah 2.52 s to run 70m and that during that 2.52 sec the gazelle would run an additional 55.9 m so that the total distance that the cheetah has to run is 125.9 meters. I've calculated that the time it takes for the cheetah to run this distance at constant speed is 4.53 s. I've redone this question about 10 times and can't figure out what I'm doing wrong. Can anyone please shed some light on what is probably a ridiculously easy question. Thank you.
 
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Kristin_Z said:

Homework Statement


A cheetah can run at approximately 100km/hr and a gazelle at 80km/hr. If both animals are running at full speed, with the gazelle 70m ahead, how long before the cheetah catches its prey?

Homework Equations


s=vt (no acceleration)
v = km/hr / 3.6 = m/s

The Attempt at a Solution


I understand that this is relative motion. I've calculated that it takes the cheetah 2.52 s to run 70m and that during that 2.52 sec the gazelle would run an additional 55.9 m so that the total distance that the cheetah has to run is 125.9 meters. I've calculated that the time it takes for the cheetah to run this distance at constant speed is 4.53 s. I've redone this question about 10 times and can't figure out what I'm doing wrong. Can anyone please shed some light on what is probably a ridiculously easy question. Thank you.

Make things simpler on yourself. Put yourself inside the head of the cheetah.

The cheetah sees dinner just 70 m away, and coming closer at the rate of 20 km/h.

Looked at another way, a student is waiting for a Pop Tart being delivered on a conveyor belt going at 20 km/h. The cafeteria worker is putting it on the conveyor from 70 m away. How long?

So how long does it take for that meal going at 20 km/h to travel 70m?
 
I've been looking at relative motion equations in 2d and having no problem but when I saw this one my brain was certain that somehow it had to be super complicated. Its not though. Thanks, is all makes sense now.
 
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