Recent content by Kys91

That's because "blonde" is the adjective for females with yellowish hair and "blond" is how you call a male with yellowish hair. :D

Well, I think there's certain dependence between it. Without money, you can't exactly have new products, eliminating expenses is not real in this world. (Money that directly goes to prototypes from the research, the researchers getting what they need for live, even if the researchers get it...

Hey Sarah, it seems you are really into rocketry. You are really serious into making it a career and not just hobby and willing to do sacrifices. I applaud you for that. Just remember, that's not only NASA or making your own company. I really think private space flight is going to take off...

Thanks, I like you used to work with the design engineer, but it was something of everyday, or when a new product came? I am impressed how much time it took to approve them, definitely they were build to really high standards. I also curious if you used to be in the factory, a special test...

Hey dlgoff, I am still in high school, but very interested in Avionics, specially radio COM and NAV. I love listening to ATC from my radio scanner and if I am near the airport I love hearing the VOR signal and imagine how cool it'd be to use the VOR with a Software Defined Radio as a cool...

Alright guys, thanks. :smile: Studying yourself + this forum is a lethal formula for learning about a lot of things.

I can solve: (2x+3y-4z)(2x-3y+4z) = [2x +(3y-4z)] [2x -(3y-4z)] = (2x)^2 -(3y-4z)^2 = (2x)^2 - (9y^2 - 24yz - 16z) = 4x^2 - 9y^2 + 24yz + 16z which is fine, but if I try to solve: (m^2-m-1)(m^2+m-1) = [m^2 -(m+1)][m^2+(m-1) = (m^2)^ 2 - (m-1)^2 = (m^2)^2 - (m^2 -2m +1) = m^4 - m^2 +2m -1...

Don't forget the cable between the Antenna and TV. High quality RG-6 it's what you need, Belden brand is nice. Keep it as short as possible, quality connectors, and tape the connector outside, you don't want water there. Maybe also you may have intermodulation problems. (For example a FM...

Thank you, much easier with putting zeros. I also noticed that I messed up a lot doing this: 0x^4 - (-3x^4) = +3x^4, I forgot to change the sign many times. Your help is very much appreciated.

I am trying to solve: \frac{x^6+6x^3-2x^5-7x^2-4x+6}{x^4-3x^2+2} Using the polynomial long division algorithm. I order first the terms of the divident, and leave one blank space between -2x^5 and +6x^3 My problem is, I first put x^2 to the quotient, so I get x^4 * x^2 = x^6, but then I...

Thanks for the responses Elucidus. My textbook doesn't include "codomain", it's an Spanish one. I am Mexican but I am glad that I have been understood even when I have to talk math concepts using English because I have never tried so, nor had a math class in English. I really admire you sir...

Wow thank you, so, they are not an equivalent function, they can't be simplified, it is literal. You could find something that would be equivalent, and maybe "simpler" to manage with the same domain, range, and express the same thing, but they would be still be different. A function is...

Suppose you have f(x) = ( x^2 + 4x + 3 ) / (x+3), making a scan in that function you can say that D : R / x =! -3, because x with -3 would give a division by zero. But, suppose you simplify that function by factorizing, you get f(x) = x + 1 It would represent the same value, but my teacher...