Recent content by Laurie01

Thank you! That makes sense.

So now I plug in: Vinduced = -dB(Lvdt) / dt Factoring out... Vinduced = -dBLv Now I'm stuck again. There is still no distance traveled by the rail involved in the problem and I don't know Vinduced. (by the way -- thank you for helping me -- I know I'm totally clueless on this problem!)

Ohhh! Duhh. Lol. Thanks so much! That helped. So, F = (0.69A)(0.34m)(.50T) = .117 N And this would be considered the "push" force? Or would it be negative since the force is acting in the opposite direction?

A = Lvdt Am I getting somewhere? So now I plug in: Vinduced = -d(Lvdt) / dt Now I'm stuck again. There is still no distance traveled by the rail involved in the problem.

Homework Statement A conducting rail in contact with conducting wires, oriented perpendicular to both wires, is pushed with constant speed, causing an induced current of 0.69 A. B = 0.50 T and R (Resistor) = 2.0 Calculate the "push" force necessary to maintain the rail's constant speed...

I am still lost. I don't see how I can use "Lvdt" when there is no variable for distance and I am solving for the velocity. I have two unknown variables in that equation. G01 -- The bar is positioned perpendicular to the rods, and it is moving inward, causing a decrease in the area of the...

Homework Statement A conducting rail in contact with zero-resistance conducting wires is pushed with constant speed, causing an induced current of 0.69A. Using Faraday's Law, calculate the rail's speed if the wires are separated by 0.34m. B = 0.50T R = 2.0Homework EquationsMagnetic Flux =...

So it would be an electron. Does an electron ever slow down as it approaches a proton in terms of it slowing down to fall into orbit?

Question: An electron is moving towards a source charge, and slows down. What is the source charge (a proton or an electron)? I feel like this question is pretty vague (because it says it moves towards the charge (making me think proton), but yet it slows down (making me think electron))...